Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Answer the following questions for the poset (2, 4, 6, 9, 12, 18, 27, 36, 48, 60, 72), 1). Find the minimal elements. (Check all that apply.) (You must provide an answer before moving to the next part.) Check All That Apply 4 6 9 12
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Part 1 of 4
Required information
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
Answer the following questions for the poset (2, 4, 6, 9, 12, 18, 27, 36, 48, 60, 72), 1).
Find the minimal elements. (Check all that apply.)
(You must provide an answer before moving to the next part.)
Check All That Apply
4
6
2
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- Add courses to the cart: Customer will only be able to add a course if the title is in the master’s list.Once added, the course name and its price need to be added to a shopping cart list, the information -title and price - needs to be separated (as in master list) by any delimiter of your choice (like: colon,space, dash etc). Customer should be able to view the shopping cart list after adding a course. Delete a course from cart: Customer will enter the name of the course and the program will lookfor the course in the shopping cart list to be deleted from. View the shopping cart list after deletion. Check out course: Customer should be able to view the list of the courses and their individualprice that are being selected by the user, then view the total price of all the courses in theshopping cart. Again, you need to use a for loop to iterate over the shopping list, separate the titleand price and view the information as shown in sample I/O. Directly printing the list will…Array Lists & Graphics: Create a project in Eclipse named Blinds. Include two classes: Rainbow and RainbowViewer. Using the colours in Table 1 in any order you want, create a 13 rows x 1 column arrangement of Rectangles (width = 500, height = 50) starting at x = 50, y = 50 with the BLACK square. Use an ArrayList to store the 13 rectangles that form the blinds. [Hint: While creating each rectangle, you can use a for loop. When ready, use the .fill method to paint them onto a JFrame (600x800) with title: “My ColourfulBlinds”.]# Create Custom Transformer Create a custom transformer, just as we did in the lecture video entitled "Custom Transformers", that performs two computations: 1. Adds an attribute to the end of the numerical data (i.e. new last column) that is equal to $\frac{x_1^3}{x_5}$ for each observation. In other words, for each instance, you will cube the $x_1$ column and then divide by the $x_5$ column. 2. Drops the entire $x_4$ feature column if the passed function argument `drop_x4` is `True` and doesn't drop the column if `drop_x4` is `False`. (See further instructions below.) You must name your custom transformer class `Assignment4Transformer`. Your class should include an input parameter called `drop_x4` with a default value of `True` that deletes the $x_4$ feature column when its value is `True`, but preserves the $x_4$ feature column when you pass a value of `False`. This transformer will be used in a pipeline. In that pipeline, an imputer will be run *before* this transformer. Keep…
- Alert -Don't submit AI generated answer and i need unique response only if I see plagiarism then I'll reduce rating for sure.For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If keysList = {42, 105, 101, 100} and itemsList = {10, 20, 30, 40}, print:20 30 Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed. #include <iostream>#include <vector>using namespace std; int main() { const int SIZE_LIST = 4; vector<int> keysList(SIZE_LIST); vector<int> itemsList(SIZE_LIST); unsigned int i; for (i = 0; i < keysList.size(); ++i) { cin >> keysList.at(i); } for (i = 0; i < itemsList.size(); ++i) { cin >> itemsList.at(i); } /* Your solution goes here */ cout << endl; return 0;}For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If keysList = {42, 105, 101, 100} and itemsList = {10, 20, 30, 40}, print: 20 30 Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed. #include <iostream>#include <vector>using namespace std; int main() {const int SIZE_LIST = 4;vector<int> keysList(SIZE_LIST);vector<int> itemsList(SIZE_LIST);unsigned int i; for (i = 0; i < keysList.size(); ++i) {cin >> keysList.at(i);} for (i = 0; i < itemsList.size(); ++i) {cin >> itemsList.at(i);} /* Your solution goes here */ cout << endl; return 0;} Please help me with this problem using c++.
- Models are used for a variety of purposes. Sort the models into groups.Chiralitydef is_left_handed(pips): Even though this has no effect on fairness, pips from one to six are not painted on dice any which way, but so that the pips on the opposite faces always add up to seven. (This convention makes it easier to tell when someone tries to use gaffed dice that leave out some spot values.) In each corner of the cube, one value from each pair of opposites 1-6, 2-5 and 3-4 meets two values from the other two pairs of opposites. The math works out correctly in for the 23 = 8 corners of the cube. This still leaves two possibilities how to paint these pips. Look at the corner shared by the faces 1, 2, and 3, and read these numbers clockwise around that corner starting from 1. If these three numbers read out as 1-2-3, that die is left-handed, and if they read out as 1-3-2, that die is right-handed. Analogous to a pair of shoes made separately for the left and right foot, left- and right-handed dice are in one sense identical, yet no matter how you twist and turn,…Implement the "Add player" menu option. Prompt the user for a new player's jersey number and rating. Append the values to the two vectors. Ex: Enter a new player's jersey number: 49 Enter the player's rating: 8
- Q3: Lecture Hall Dan holds his CSC108 lectures in a rectangular N X M lecture hall. In other words, this lecture hall has N rows of seats, each of them containing exactly M seats. Here's my attempt at drawing this layout when N = 3 and M = 5: Dan Off 00 lecture hall layout with 3 rows and 5 seats per row The rows are numbered from 1 to N starting from the front row. Similarly, the columns are numbered from 1 to M starting from the leftmost column. We write (r, c) to denote the c-th seat in the r-th row. When Dan walks into the lecture hall this morning, some of the seats are already taken (this is the initial layout of the lecture hall). After that, the students come in one group at a time. From experience, Dan knows that when a group of K students enter the lecture hall, they look for K consecutive empty seats. That is, they try to find an empty seat (r, c) such that for all integers i in [0, K-1], the seat (r, c + 1) exists and is empty. If they can't find K consecutive empty seats,…3.)Declare variables a. The images variable containing an HTML collection of all elements with the tag name "img". b. The photoBucket variable referencing the element with the id "photo_bucket". c. The photoList variable referencing the element with the id "photo_list". 4.) Create a for loop that iterates through all of the items in the images collection. 5.) Within the for loop insert an onclick event handler that runs an anonymous function when an image is clicked. 6.) When an image is clicked it is either moved from the photo bucket to the photo list or from the photo list back to the photo bucket. To determine which action to perform, add the following if else statement to the anonymous function: a. If the parent element of the clicked image has an id equal to "photo_bucket" then do the following: (i) Create an element node named newltem for the li element, (ii) append newltem to the photoList object, and (i) append the image to the newltem object using the appendChild() method.…Lists at_bus_stop and on_board are read from input, representing passengers waiting to board a bus and passengers on the bus, respectively. Perform the following tasks: Remove the first element from at_bus_stop and output 'Passenger left bus stop: ' followed by the element. Add all the remaining elements of at_bus_stop to the end of on_board.