Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Answer the following questions for the poset (2, 4, 6, 9, 12, 18, 27, 36, 48, 60, 72), 1). Find the minimal elements. (Check all that apply.) (You must provide an answer before moving to the next part.) Check All That Apply 4 6 9 12

Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Answer the following questions for the poset (2, 4, 6, 9, 12, 18, 27, 36, 48, 60, 72), 1). Find the minimal elements. (Check all that apply.) (You must provide an answer before moving to the next part.) Check All That Apply 4 6 9 12

COMPREHENSIVE MICROSOFT OFFICE 365 EXCE

1st Edition

ISBN:9780357392676

Author:FREUND, Steven

Publisher:FREUND, Steven

Chapter8: Working With Trendlines, Pivottables, Pivotcharts, And Slicers

Section: Chapter Questions

Problem 8EYW

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Add courses to the cart: Customer will only be able to add a course if the title is in the master’s list.Once added, the course name and its price need to be added to a shopping cart list, the information -title and price - needs to be separated (as in master list) by any delimiter of your choice (like: colon,space, dash etc). Customer should be able to view the shopping cart list after adding a course. Delete a course from cart: Customer will enter the name of the course and the program will lookfor the course in the shopping cart list to be deleted from. View the shopping cart list after deletion. Check out course: Customer should be able to view the list of the courses and their individualprice that are being selected by the user, then view the total price of all the courses in theshopping cart. Again, you need to use a for loop to iterate over the shopping list, separate the titleand price and view the information as shown in sample I/O. Directly printing the list will…
Array Lists & Graphics: Create a project in Eclipse named Blinds. Include two classes: Rainbow and RainbowViewer. Using the colours in Table 1 in any order you want, create a 13 rows x 1 column arrangement of Rectangles (width = 500, height = 50) starting at x = 50, y = 50 with the BLACK square. Use an ArrayList to store the 13 rectangles that form the blinds. [Hint: While creating each rectangle, you can use a for loop. When ready, use the .fill method to paint them onto a JFrame (600x800) with title: “My ColourfulBlinds”.]
# Create Custom Transformer Create a custom transformer, just as we did in the lecture video entitled "Custom Transformers", that performs two computations: 1. Adds an attribute to the end of the numerical data (i.e. new last column) that is equal to $\frac{x_1^3}{x_5}$ for each observation. In other words, for each instance, you will cube the $x_1$ column and then divide by the $x_5$ column. 2. Drops the entire $x_4$ feature column if the passed function argument `drop_x4` is `True` and doesn't drop the column if `drop_x4` is `False`. (See further instructions below.) You must name your custom transformer class `Assignment4Transformer`. Your class should include an input parameter called `drop_x4` with a default value of `True` that deletes the $x_4$ feature column when its value is `True`, but preserves the $x_4$ feature column when you pass a value of `False`. This transformer will be used in a pipeline. In that pipeline, an imputer will be run *before* this transformer. Keep…
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For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If keysList = {42, 105, 101, 100} and itemsList = {10, 20, 30, 40}, print:20 30 Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed. #include <iostream>#include <vector>using namespace std; int main() { const int SIZE_LIST = 4; vector<int> keysList(SIZE_LIST); vector<int> itemsList(SIZE_LIST); unsigned int i; for (i = 0; i < keysList.size(); ++i) { cin >> keysList.at(i); } for (i = 0; i < itemsList.size(); ++i) { cin >> itemsList.at(i); } /* Your solution goes here */ cout << endl; return 0;}
For any element in keysList with a value greater than 100, print the corresponding value in itemsList, followed by a space. Ex: If keysList = {42, 105, 101, 100} and itemsList = {10, 20, 30, 40}, print: 20 30 Since keysList.at(1) and keysList.at(2) have values greater than 100, the value of itemsList.at(1) and itemsList.at(2) are printed. #include <iostream>#include <vector>using namespace std; int main() {const int SIZE_LIST = 4;vector<int> keysList(SIZE_LIST);vector<int> itemsList(SIZE_LIST);unsigned int i; for (i = 0; i < keysList.size(); ++i) {cin >> keysList.at(i);} for (i = 0; i < itemsList.size(); ++i) {cin >> itemsList.at(i);} /* Your solution goes here */ cout << endl; return 0;} Please help me with this problem using c++.
Models are used for a variety of purposes. Sort the models into groups.
Chiralitydef is_left_handed(pips): Even though this has no effect on fairness, pips from one to six are not painted on dice any which way, but so that the pips on the opposite faces always add up to seven. (This convention makes it easier to tell when someone tries to use gaffed dice that leave out some spot values.) In each corner of the cube, one value from each pair of opposites 1-6, 2-5 and 3-4 meets two values from the other two pairs of opposites. The math works out correctly in for the 23 = 8 corners of the cube. This still leaves two possibilities how to paint these pips. Look at the corner shared by the faces 1, 2, and 3, and read these numbers clockwise around that corner starting from 1. If these three numbers read out as 1-2-3, that die is left-handed, and if they read out as 1-3-2, that die is right-handed. Analogous to a pair of shoes made separately for the left and right foot, left- and right-handed dice are in one sense identical, yet no matter how you twist and turn,…
Implement the "Add player" menu option. Prompt the user for a new player's jersey number and rating. Append the values to the two vectors. Ex: Enter a new player's jersey number: 49 Enter the player's rating: 8
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