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Required information Consider the figure given below: ЗА Q23 Q2 Q24 R Q20 Q21 A A R2 O-VEE %3D What are the three bias currents in the source in the given figure if R = 100 k2, R2 = 4 kN, and Vcc= VEE= 4 V. |HA (Round off the solution to the nearest integer.) | HA (Round off the solution to the nearest integer.) |HA (Round off the solution to the nearest integer.) | HA (Round off the solution to the nearest integer.) | HA (Round off the solution to one decimal place.) Ic20 =| IC22 = Ic23 Ic24 =

Required information Consider the figure given below: ЗА Q23 Q2 Q24 R Q20 Q21 A A R2 O-VEE %3D What are the three bias currents in the source in the given figure if R = 100 k2, R2 = 4 kN, and Vcc= VEE= 4 V. |HA (Round off the solution to the nearest integer.) | HA (Round off the solution to the nearest integer.) |HA (Round off the solution to the nearest integer.) | HA (Round off the solution to the nearest integer.) | HA (Round off the solution to one decimal place.) Ic20 =| IC22 = Ic23 Ic24 =

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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15. I included a book reference for the formulas:

What are the three bias currents in the source in the given figure if R1 = 100 kQ, R2 = 4 kN, and Vcc = VEE = 25 V. Ic20 = Ic22 Ic23 IC24 486 µA (Round off the solution to the nearest integer.) 486 µA (Round off the solution to the nearest integer.) 1458 µA (Round off the solution to the nearest integer.) 486 µA (Round off the solution to the nearest integer.) 20 HA (Round off the solution to one decimal place.) Explanation: Ic22 = Ic20 Voc-VEB22-VBE20-(-VEE) 25V-0.7-0.7-(-25V) 486 μΑ Ic23 = 3Ic22 = 1458 µA | Ic24 - Ic2 100k 486 μΑ %3D 486 µA 486 μΑ -ln 4kn Ic 0.025V (A) = 6.25µAIn ) - 1 = 20 µA
Transcribed Image Text:What are the three bias currents in the source in the given figure if R1 = 100 kQ, R2 = 4 kN, and Vcc = VEE = 25 V. Ic20 = Ic22 Ic23 IC24 486 µA (Round off the solution to the nearest integer.) 486 µA (Round off the solution to the nearest integer.) 1458 µA (Round off the solution to the nearest integer.) 486 µA (Round off the solution to the nearest integer.) 20 HA (Round off the solution to one decimal place.) Explanation: Ic22 = Ic20 Voc-VEB22-VBE20-(-VEE) 25V-0.7-0.7-(-25V) 486 μΑ Ic23 = 3Ic22 = 1458 µA | Ic24 - Ic2 100k 486 μΑ %3D 486 µA 486 μΑ -ln 4kn Ic 0.025V (A) = 6.25µAIn ) - 1 = 20 µA
! Required information Consider the figure given below: +Vc A ЗА Q23 Q24 2 R| Q20 Q21 A R2 -VEE What are the three bias currents in the source in the given figure if R1 = 100 k2, R2 = 4 kQ, and Vcc= VEE= 4 V. HA (Round off the solution to the nearest integer.) HA (Round off the solution to the nearest integer.) |µA (Round off the solution to the nearest integer.) |HA (Round off the solution to the nearest integer.) |HA (Round off the solution to one decimal place.) IC20 = IC22 IC23 = IC24
Transcribed Image Text:! Required information Consider the figure given below: +Vc A ЗА Q23 Q24 2 R| Q20 Q21 A R2 -VEE What are the three bias currents in the source in the given figure if R1 = 100 k2, R2 = 4 kQ, and Vcc= VEE= 4 V. HA (Round off the solution to the nearest integer.) HA (Round off the solution to the nearest integer.) |µA (Round off the solution to the nearest integer.) |HA (Round off the solution to the nearest integer.) |HA (Round off the solution to one decimal place.) IC20 = IC22 IC23 = IC24
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