! Required information An object is placed 20.0 cm from a converging lens with focal length 15.0 cm (see the figure, not drawn to scale). A concave mirror with focal length 10.0 cm is located 79.5 cm to the right of the lens. Light goes through the lens, reflects from the mirror, and passes through the lens again, forming a final image. Converging lens Object Concave mirror 15.0 cm -20.0 cm- 10.0 cm d cm d = 79.5. What is the location of the final image? cm to the left of the lens
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- Current Attempt in Progress A point object is 11 cm away from a plane mirror, and the eye of an observer (with pupil diameter 6.4 mm) is 26 cm away. Assuming the eye and the object to be on the same line perpendicular to the mirror surface, find the area of the mirror used in observing the reflection of the point. (Hint: Adapt the figure below.) Number i Units MirrorDIVERGING LENS An object measuring 15 cm in height is placed in front of a diverging lens. An upright, virtual image with a height of 8 cm is seen on the same side of the lens as the object. a) What is the magnification of the lens? b) If the object is 35 cm away, where is the image? c) Based on the above, what is the focal length of the lens? d) Starting with the object's height and distance from the lens, draw a scale diagram of the situation.Question in the image
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- Lenses questionMY NOTES ASK YOUR TEACHER PRACTICE ANOTHER If a converging lens forms a real, inverted image 24.0 cm to the right of the lens when the object is placed 42.0 cm to the left of a lens, determine the focal length of the lens. cm Additional Materials M ReadingMirrors & Lenses You want to order a mirror for your bathroom which produces an upright image which is magnified by a factor of 2.0 (see chapter 23.5 for more detail about magnification) when held 20 cm from your face. Use a ray diagram to represent this situation and say what type of mirror you would need and what its focal length should be. Scientific Abilities Missing Inadequate D Needs Improvement Adequate