! Required information An insulated heated rod with spatially heat source can be modeled with the Poisson equation. d² dx² Given: A heat source f(x) = 0.12x³ — 2.4x² + 12x and the boundary conditions T(x=0) = 40°C and 7(x = 10) = 200 °C T = -f(x) Solve the ODE using the shooting method. (Round the final answer to four decimal places.) Use 4th order Runge Kutta. The temperature distribution at x = 2 is K.
! Required information An insulated heated rod with spatially heat source can be modeled with the Poisson equation. d² dx² Given: A heat source f(x) = 0.12x³ — 2.4x² + 12x and the boundary conditions T(x=0) = 40°C and 7(x = 10) = 200 °C T = -f(x) Solve the ODE using the shooting method. (Round the final answer to four decimal places.) Use 4th order Runge Kutta. The temperature distribution at x = 2 is K.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Required information
An insulated heated rod with spatially heat source can be modeled with the Poisson equation.
d² T
dx²
- f (x)
Given: A heat source f(x) = 0.12x³ − 2.4x² + 12x and the boundary conditions T(x = 0) = 40°C and 7(x = 10) = 200 °C
Solve the ODE using the shooting method. (Round the final answer to four decimal places.) Use 4th order Runge Kutta.
The temperature distribution at x = 2 is
K.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc868b49e-bf14-41d8-a7dc-0dd3130d6d03%2F5909fbd0-262f-4784-b416-2938a5d05e1e%2F5o3f61j_processed.png&w=3840&q=75)
Transcribed Image Text:!
Required information
An insulated heated rod with spatially heat source can be modeled with the Poisson equation.
d² T
dx²
- f (x)
Given: A heat source f(x) = 0.12x³ − 2.4x² + 12x and the boundary conditions T(x = 0) = 40°C and 7(x = 10) = 200 °C
Solve the ODE using the shooting method. (Round the final answer to four decimal places.) Use 4th order Runge Kutta.
The temperature distribution at x = 2 is
K.
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