Required information A contractor uses a paddle stirrer to mix a can of paint. The paddle turns at 28.0 rad/s and exerts a torque of 17.0 Nm on the paint, doing work on the paint at a rate of Power Ta-170 Nm 28.0 rad/s-476.0 W. An internal energy increase of 13.9 kJ causes the temperature of the paint to increase by 1.00 K. If the actual temperature change was 6.30 K, how much heat flowed from the paint to the surroundings as it is stirred for 5.00 min? Enter the value of Qin kJ, where positive indicates heat flows into the paint and negative indicates heat flows out of the paint. KJ

icon
Related questions
Question
M4
Required information
A contractor uses a paddle stirrer to mix a can of paint. The paddle turns at 28.0 rad/s and exerts a torque of 17.0 Nm on
the paint, doing work on the paint at a rate of Power - Tw-17.0 Nm 28.0 rad/s-476.0 W. An internal energy increase of
13.9 kJ causes the temperature of the paint to increase by 1.00 K.
If the actual temperature change was 6.30 K, how much heat flowed from the paint to the surroundings as it is stirred for 5.00
min? Enter the value of Qin kJ, where positive indicates heat flows into the paint and negative indicates heat flows out of the paint.
876 kJ
Transcribed Image Text:Required information A contractor uses a paddle stirrer to mix a can of paint. The paddle turns at 28.0 rad/s and exerts a torque of 17.0 Nm on the paint, doing work on the paint at a rate of Power - Tw-17.0 Nm 28.0 rad/s-476.0 W. An internal energy increase of 13.9 kJ causes the temperature of the paint to increase by 1.00 K. If the actual temperature change was 6.30 K, how much heat flowed from the paint to the surroundings as it is stirred for 5.00 min? Enter the value of Qin kJ, where positive indicates heat flows into the paint and negative indicates heat flows out of the paint. 876 kJ
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer