Replace the system of forces and couples in the figure with an equivalent force-couple system at B.
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- PROBLEMS 2-7.2. In Fig. P-2-7.2, a boom AC is supported by a ball-and-socket joint at C and by the cables BE and AD. If the force multiplier of a force F acting from B to E is F A to D is P = 10 lb/ft and that of a force P acting from = 20 lb/ft, find the component of each force along AC. %3D %3D FAC -37.5 lb; PAC =D100 lb Ans. %3D %3D problem ble indQ2 / A shaft transmitting 15kW at 200r.p.m. are supported by two bearings placed 1 m apart. A 600 mm diameter pulley is mounted at a distance of 300 mm to the right of left hand bearing and this drives a pulley directly below it with the help of belt having maximum tension of 2.25kN. Another pulley 400 mm diameter is placed 200 mm to the left of right hand bearing and is driven with the help of electric motor and belt having maximum tension of 3.376kN, which is placed horizontally to the right. The angle of contact for both the pulleys is180° and =0.24. Determine the suitable diameter for a solid shaft if the bending moment acting on the shaft is reversed, allowing working stress of 42MPA in shear for the material of shaft and have yield stress of 400MPA and ultimate stress of 500MP.. And design the keys which support each pulley if the material of the keys is the same for the material of shaft.Solved Examples 8KN Example 5 Replace the force and couple moment system acting on the beam in the figure below by an equivalent resultant force, and find where its line of action intersects the beam, measured from point O. 4KN 15 KN-m (0,5 m Solution:- Force Summation. Summing the force components, 1.5 m 1.5 m 15 m 15m F), = XF;; (F), = 8 kN(}) = 4.80 kNO
- :Q81 The moment M for the force the figure shown below is 250 N 153 -200 mm 30 mm 46.5 N.M O 46.6 N.M O 46.4N. M of L iskW at 360 rpm from the pulley 1 to the pulley 2. The diameters of pulleys 1 and 2 are 250 mm and 500 mm Q1:A shaft carry ing two pulleys I and 2, and supported on two bearings A and B. The shaft transmits a power of 7.5 respectively. The masses of pulleys 1 and 2 are 10 ko qnd 30 kg respectively. The belt tensions act vertically downward and the ratio of belt tensions on the tight si alack side for each pulley is 2.5:1. The shaft is made of plain carbon steel, the Permissible shear stress is 63.333 MMPg and the factor of safety is . 1- Find the total force acting at the centre line of the pulley I and 2 and 2- Estimate suitable diameter of shaft, Assume G = 79300 MPa. 250 500 250 Px 60 T = 2n N 2.3 log = L1.0 3 (T-T,) Rc (а) T = JM? +T IxTx d =-X 16 T T1 Tz T3 |र---.36 l? N 1:4 0 p 12:02 يستخدم التطبيق المیکروفون Me et docs.google.com/forms/c Q1: Four forces and a couple are acting on a rectangular plate as shown, replace the forces and the couple by an equivalent force - couple system at bolt 1. 400 N 30 1000 N 0.6 m 100 N.m 600 N O1 250 N Im إضافة ملف Q2 / The boom is intended to support two vertical loads, F, and F2. If the cable CB can sustain a maximum load of 1500 N before it fails, determine the critical loads if F, = 2F,. Also, what is the magnitude of the reaction at support A? 1.5m 30 إضافة ملف
- By moment-distribution method. Use exact values of the relative k's, whichever comes first. w1 = 25 KN/m w2 = 35 KN/m, w3 = 10.5 KN/m. 82 KN 65 KN 85 KN 70 KN 75 KN W2 W3 W1 B 120m| D 100m 2. 40 m |1.00m| 1.80 m 2.0m 1.40 m 2. 40 m 2.0 m7 ft I 3 Yo 66 k 4f+ 2ft 3ff Find force for all member? (Q₁) доки B 60⁰° 20 lookN U 50 g 80° C 6 3% 200KN EThe rectangular framework is subjected to the following non-concurrent system of forces: a 30lb- force below the origin, a 20 lb-force,3ft above the origin and making an angle of30°N of E, a 100lb-force with a horizontal distance of 3ft and a vertical distance of 4ftfrom the origin and making an angle of 45°NW , a 60lb -force with the same distance like the previous force but along the positive x-axis, and a 100lb- force 4ft tothe right of the origin and making an angle of 60° S of W . Determine the magnitude and direction of the resultant, as well as its moment arm relative to the origin.
- LTE I. A:E7 A docs.google.com The two forces are equivalent to a force R that has a line of action passing * .through point A 0.2 m 120 N 4 90 N 0.1 m R=150 N, x=0.133 m O R=150 N, x=0.1 m R=150 N, x-0.075 m None of these The tension in cables BA necessary .3 * to support the 60-kg cylinder isQ2 / A belt drive consist of two V-belts in parallei, on grooved pulleys of the same size. The angle of the groove is 30". The cross - section area of each belt is 750 mm? and u is 0.12. The density of the belt material is 1.2 Mg/m' and the maximum safe stress in the material is 7 MN/m. Answer the following questions 1- The centrifugal tension in belts is . . (a) increases power transmitted (b) decreases power transmitted (e) have no effect on power transmitted (d) increases power transmitted up to a certain speed and then decreasesIn the graph the force versus displacement of a spring is given (the spring is shown in a separate figure--see below). The x-axis range is ±2 cm. The y-axis range is tFs, where Fs = 220 N. How much work does the spring do on the block (the mass "m") when the block moves from x₁ = 7.6 cm to 4.3 cm? W J y F. X -1.5 -0.5 0 10.5 1 1.5 -F How much work does the spring do on the block (the mass "m") when the block moves from x; = 7.6 cm to -7.6 cm? W = Question Help: Read Submit Question m