) Replace the loading on the member by an equivalent resultant force (indicate the magnitude and direction of the force) and a couple moment (indicate the magnitude and direction of the moment) acting at point A. 200 lb 150 L
) Replace the loading on the member by an equivalent resultant force (indicate the magnitude and direction of the force) and a couple moment (indicate the magnitude and direction of the moment) acting at point A. 200 lb 150 L
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![### Problem Description:
Replace the loading on the member by an equivalent resultant force (indicate the magnitude and direction of the force) and a couple moment (indicate the magnitude and direction of the moment) acting at point **A**.
### Diagram Explanation:
The diagram depicts a mechanical member with multiple forces acting upon it. These forces and distances are:
- **Forces:**
- **200 lb** force acting upwards with an angle of **30°** from horizontal at a distance of **3 ft** from point **A**.
- **150 lb** force acting upwards, at point **B** with the direction forming a **3:4:5** right triangle.
- **100 lb** force acting downwards with an angle of **30°** from horizontal at a distance of **4 ft** from point **A**.
- **120 lb** force acting upwards with the direction forming a **3:4:5** right triangle.
- A couple moment of **200 lb·ft** acting clockwise at point **A**.
- **Distances:**
- The entire horizontal length from point **A** to point **B** is **4 ft** with an additional **3 ft** extending beyond point **B**.
- The vertical distance from point **B** down to the horizontal extension is **4 ft**.
### Steps to Find Equivalent Resultant Force and Moment:
1. **Determine Resultant Force Vector:**
- Resolve all forces into their horizontal (x) and vertical (y) components.
- Sum up all the x-components to get the resultant force in the x-direction, \( F_{Rx} \).
- Sum up all the y-components to get the resultant force in the y-direction, \( F_{Ry} \).
2. **Calculate the Magnitudes:**
- Resultant force magnitude, \( F_R = \sqrt{F_{Rx}^2 + F_{Ry}^2} \).
- Resultant force direction, \( \theta = \tan^{-1}(\frac{F_{Ry}}{F_{Rx}}) \).
3. **Calculate Resultant Moment:**
- Sum the moments about point **A** considering the force and their respective perpendicular distances to **A**.
The specific calculations depend on the detailed set of equations set up for each force component and their corresponding distances.
### Summary:
Replacing these forces with an equivalent](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbad2734e-649a-4533-b9cc-3c645832697e%2F320fe748-91aa-4498-89b6-61a53b9e40b6%2Ffhgw3eg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem Description:
Replace the loading on the member by an equivalent resultant force (indicate the magnitude and direction of the force) and a couple moment (indicate the magnitude and direction of the moment) acting at point **A**.
### Diagram Explanation:
The diagram depicts a mechanical member with multiple forces acting upon it. These forces and distances are:
- **Forces:**
- **200 lb** force acting upwards with an angle of **30°** from horizontal at a distance of **3 ft** from point **A**.
- **150 lb** force acting upwards, at point **B** with the direction forming a **3:4:5** right triangle.
- **100 lb** force acting downwards with an angle of **30°** from horizontal at a distance of **4 ft** from point **A**.
- **120 lb** force acting upwards with the direction forming a **3:4:5** right triangle.
- A couple moment of **200 lb·ft** acting clockwise at point **A**.
- **Distances:**
- The entire horizontal length from point **A** to point **B** is **4 ft** with an additional **3 ft** extending beyond point **B**.
- The vertical distance from point **B** down to the horizontal extension is **4 ft**.
### Steps to Find Equivalent Resultant Force and Moment:
1. **Determine Resultant Force Vector:**
- Resolve all forces into their horizontal (x) and vertical (y) components.
- Sum up all the x-components to get the resultant force in the x-direction, \( F_{Rx} \).
- Sum up all the y-components to get the resultant force in the y-direction, \( F_{Ry} \).
2. **Calculate the Magnitudes:**
- Resultant force magnitude, \( F_R = \sqrt{F_{Rx}^2 + F_{Ry}^2} \).
- Resultant force direction, \( \theta = \tan^{-1}(\frac{F_{Ry}}{F_{Rx}}) \).
3. **Calculate Resultant Moment:**
- Sum the moments about point **A** considering the force and their respective perpendicular distances to **A**.
The specific calculations depend on the detailed set of equations set up for each force component and their corresponding distances.
### Summary:
Replacing these forces with an equivalent
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