4.) Please help with question ### Analysis of Forces on a Vertical PostThis diagram illustrates the application of forces on a vertical wooden post anchored at point O. The post is subjected to three distinct forces:1. **Force at the Top:** - A force of 200 lb is applied at the top of the post. - This force is directed at an angle of 30 degrees above the horizontal.2. **Middle Force:** - A horizontal force of 300 lb acts 2 feet below the top of the post.3. **Lower Force:** - At 4 feet below the top, there is a force of 250 lb. - This force is directed at an angle, with a rise and run indicated as a 3-4-5 triangle, suggesting the force is acting at an angle where the components form a ratio of 3:4:5.#### Distance Measurements:- The forces are positioned at specific intervals along the post: - The top force is 2 feet from the middle force. - The middle force is 2 feet from the lower force. - The entire post length related to applied forces is thus segmented into 2-foot intervals.These details are critical for understanding the distribution of forces and moments along the post, which is helpful for calculating resulting stresses and ensuring structural integrity in engineering applications. **Title: Analyzing Forces and Moments in Structural Systems****Objective:**Replace the force system on the post with a resultant force, \( F_R \), and a couple moment, \( M_R \), about point O.**Diagram Description:**The diagram illustrates a vertical post secured at its base, labeled as point O. Multiple forces are applied at different points on the post. These include:1. A force of 200 lb applied at the top of the post at a 30° angle from the horizontal, 4 feet above O.2. A force of 250 lb applied perpendicularly to the left at an unspecified height, indicated with directional components using a 3-4-5 triangle (suggesting the use of trigonometric components).3. A horizontal force of 300 lb applied to the right, 2 feet above O.4. The post height is divided into a section of 2 feet from O to the first horizontal force application and another 2 feet to the force at the top.**Analysis Steps:**1. **Determine Resultant Force \( F_R \):** - Break down angled forces into horizontal and vertical components using trigonometric functions (e.g., sin, cos for 30°). - Sum all horizontal and vertical force components to find the overall resultant force vector.2. **Calculate Couple Moment \( M_R \) about Point O:** - For each force, calculate the moment about point O. Moment is given by the perpendicular force component multiplied by the distance from point O. - Use the right-hand rule to determine the direction of each moment. - Sum all moments to find the resultant moment about point O.**Application:**Understanding how to simplify a complex force system into a resultant force and moment is essential in structural engineering, helping in analyzing and designing structural elements for safety and efficiency.

To be found out:- Resultant force Moment at point O

Answered: Replace the force system on the post by…

Replace the force system on the post by a resultant force, FR, and couple moment, MR, about point O. 250 lb 3 20 O- 200 lb 30° 2 ftrumen + 2 ft 2 ft the 300 lb

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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