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Reorder the transfer function (shown below) using the values for the Black disk to the form Here C is just a constant. Q(s) Vt(s) = Kt Rajs +Kt*Kb Values for Black disk Below Ra = 25 Kt = 0.0281 Kb = 0.0312 J = 3.248 x 10-5 Had the answer correct which is = 32.0531 0.9265 + 1 Just step by step how to get the answer C TS + 1

Reorder the transfer function (shown below) using the values for the Black disk to the form Here C is just a constant. Q(s) Vt(s) = Kt Rajs +Kt*Kb Values for Black disk Below Ra = 25 Kt = 0.0281 Kb = 0.0312 J = 3.248 x 10-5 Had the answer correct which is = 32.0531 0.9265 + 1 Just step by step how to get the answer C TS + 1

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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### Reordering the Transfer Function To reorder the transfer function for the Black disk, we use the formula to match the form \( \frac{C}{\tau s + 1} \), where \( C \) is a constant. Given transfer function: \[ \frac{\Omega(s)}{Vt(s)} = \frac{Kt}{RaJs + Kt \times Kb} \] #### Values for Black Disk - \( Ra = 25 \) - \( Kt = 0.0281 \) - \( Kb = 0.0312 \) - \( J = 3.248 \times 10^{-5} \) #### Correct Answer The reordered transfer function should be: \[ \frac{32.0531}{0.9265s + 1} \] #### Steps to Find the Answer 1. **Substitute Values**: Insert the given values of \( Ra \), \( Kt \), \( Kb \), and \( J \) into the transfer function. 2. **Simplify**: Perform algebraic manipulation to simplify the expression to the desired form. 3. **Compare & Adjust**: Match the coefficients to achieve the form \( \frac{C}{\tau s + 1} \). By following these steps, the correct transfer function form is obtained.
Transcribed Image Text:### Reordering the Transfer Function To reorder the transfer function for the Black disk, we use the formula to match the form \( \frac{C}{\tau s + 1} \), where \( C \) is a constant. Given transfer function: \[ \frac{\Omega(s)}{Vt(s)} = \frac{Kt}{RaJs + Kt \times Kb} \] #### Values for Black Disk - \( Ra = 25 \) - \( Kt = 0.0281 \) - \( Kb = 0.0312 \) - \( J = 3.248 \times 10^{-5} \) #### Correct Answer The reordered transfer function should be: \[ \frac{32.0531}{0.9265s + 1} \] #### Steps to Find the Answer 1. **Substitute Values**: Insert the given values of \( Ra \), \( Kt \), \( Kb \), and \( J \) into the transfer function. 2. **Simplify**: Perform algebraic manipulation to simplify the expression to the desired form. 3. **Compare & Adjust**: Match the coefficients to achieve the form \( \frac{C}{\tau s + 1} \). By following these steps, the correct transfer function form is obtained.
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