Remy is catering food for a party. The catering company charges $75 plus $7.50 per guest. If Remy wants to spend under $300 for food, how many guests aan she invite? 7.5x + 75 < 300 300 -7.5x 275 2Joshua has $300 in a checking account and he withdraws $7.50 per week. How many weeks can Joshua continue ta withdraw money and still have a minimum of $75 in his account ? 7.5x + 75 2 300 300 - 7.5x s75 3 Gordon is selling popcorn that costs $7.50 per bag as a fundraiser. He has already sold $75 worth of popcorn, and if he sells over $300 worth, he will win a prize. How many more bags does Gordon need to sell to win a prize? 7.5x + 76 > 300

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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## Inequality Matching Activity

### Instructions:
Draw a line to match each situation to the inequality that correctly represents it and to the solution. Note that not all choices will be used.

### Situations:
1. **Remy is catering food for a party**  
   The catering company charges $75 plus $7.50 per guest. If Remy wants to spend under $300 for food, how many guests can she invite?

2. **Joshua has $300 in a checking account**  
   He withdraws $7.50 per week. How many weeks can Joshua continue to withdraw money and still have a minimum of $75 in his account?

3. **Gordon is selling popcorn that costs $7.50 per bag as a fundraiser**  
   He has already sold $75 worth of popcorn, and if he sells over $300 worth, he will win a prize. How many more bags does Gordon need to sell to win a prize?

### Inequalities:
- \( 7.5x + 75 < 300 \)
- \( 300 - 7.5x \geq 75 \)
- \( 7.5x + 75 > 300 \)

### Solutions:
- \( x \leq 30 \)
- \( x \leq 30 \)
- \( x \geq 30 \)

---

The diagram in the image shows lines drawn to match each situation to the correct inequality and solution as follows:

- **Situation 1 (Remy and Catering)**:
  - Matched Inequality: \( 7.5x + 75 < 300 \)
  - Matched Solution: \( x \leq 30 \)

- **Situation 2 (Joshua and Checking Account)**:
  - Matched Inequality: \( 300 - 7.5x \geq 75 \)
  - Matched Solution: \( x \leq 30 \)

- **Situation 3 (Gordon and Popcorn Sales)**:
  - Matched Inequality: \( 7.5x + 75 > 300 \)
  - Matched Solution: \( x \geq 30 \)

For educational purposes, you can visualize these matches by drawing lines connecting each situation (on the left) to its corresponding inequality (in the middle) and then to its solution (on the right).

---
Transcribed Image Text:--- ## Inequality Matching Activity ### Instructions: Draw a line to match each situation to the inequality that correctly represents it and to the solution. Note that not all choices will be used. ### Situations: 1. **Remy is catering food for a party** The catering company charges $75 plus $7.50 per guest. If Remy wants to spend under $300 for food, how many guests can she invite? 2. **Joshua has $300 in a checking account** He withdraws $7.50 per week. How many weeks can Joshua continue to withdraw money and still have a minimum of $75 in his account? 3. **Gordon is selling popcorn that costs $7.50 per bag as a fundraiser** He has already sold $75 worth of popcorn, and if he sells over $300 worth, he will win a prize. How many more bags does Gordon need to sell to win a prize? ### Inequalities: - \( 7.5x + 75 < 300 \) - \( 300 - 7.5x \geq 75 \) - \( 7.5x + 75 > 300 \) ### Solutions: - \( x \leq 30 \) - \( x \leq 30 \) - \( x \geq 30 \) --- The diagram in the image shows lines drawn to match each situation to the correct inequality and solution as follows: - **Situation 1 (Remy and Catering)**: - Matched Inequality: \( 7.5x + 75 < 300 \) - Matched Solution: \( x \leq 30 \) - **Situation 2 (Joshua and Checking Account)**: - Matched Inequality: \( 300 - 7.5x \geq 75 \) - Matched Solution: \( x \leq 30 \) - **Situation 3 (Gordon and Popcorn Sales)**: - Matched Inequality: \( 7.5x + 75 > 300 \) - Matched Solution: \( x \geq 30 \) For educational purposes, you can visualize these matches by drawing lines connecting each situation (on the left) to its corresponding inequality (in the middle) and then to its solution (on the right). ---
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