Remember that B (n, p) → P(x) = (")p²q¹-² with the Binomial Coefficient n! (2)= So for example: (39) = 10! 3!(10-3)! = 10! 31-7! = 10-9-8-7! 3!-7! = 10-9-8 3! = 10-9-8 3-2-1 = 10.3.4 = 120 Thus given B (10, 0.4) and want to Find P(3) -> P (3) = (3)0.4³ (1-0.4) ¹0-3 = 120 0.4³ -0.67≈ 0.215 Given that you have B(7, 0.712) find P(3) to the nearest thousandth
Remember that B (n, p) → P(x) = (")p²q¹-² with the Binomial Coefficient n! (2)= So for example: (39) = 10! 3!(10-3)! = 10! 31-7! = 10-9-8-7! 3!-7! = 10-9-8 3! = 10-9-8 3-2-1 = 10.3.4 = 120 Thus given B (10, 0.4) and want to Find P(3) -> P (3) = (3)0.4³ (1-0.4) ¹0-3 = 120 0.4³ -0.67≈ 0.215 Given that you have B(7, 0.712) find P(3) to the nearest thousandth
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![**Question 13**
Remember that \( B(n, p) \rightarrow P(x) = \binom{n}{x} p^x q^{n-x} \) with the Binomial Coefficient
\[
\binom{n}{x} \equiv \frac{n!}{x!(n-x)!}
\]
So for example:
\[
\binom{10}{3} = \frac{10!}{3!(10-3)!} = \frac{10 \cdot 9 \cdot 8 \cdot 7!}{3! \cdot 7!} = \frac{10 \cdot 9 \cdot 8}{3!} = \frac{10 \cdot 9 \cdot 8}{3 \cdot 2 \cdot 1} = 10 \cdot 3 \cdot 4 = 120
\]
Thus given \( B(10, 0.4) \) and want to Find P(3):
\[
P(3) = \binom{10}{3} 0.4^3 (1 - 0.4)^{10-3} = 120 \cdot 0.4^3 \cdot 0.6^7 \approx 0.215
\]
Given that you have \( B(7, 0.712) \) find P(3) to the nearest thousandth
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Transcribed Image Text:**Question 13**
Remember that \( B(n, p) \rightarrow P(x) = \binom{n}{x} p^x q^{n-x} \) with the Binomial Coefficient
\[
\binom{n}{x} \equiv \frac{n!}{x!(n-x)!}
\]
So for example:
\[
\binom{10}{3} = \frac{10!}{3!(10-3)!} = \frac{10 \cdot 9 \cdot 8 \cdot 7!}{3! \cdot 7!} = \frac{10 \cdot 9 \cdot 8}{3!} = \frac{10 \cdot 9 \cdot 8}{3 \cdot 2 \cdot 1} = 10 \cdot 3 \cdot 4 = 120
\]
Thus given \( B(10, 0.4) \) and want to Find P(3):
\[
P(3) = \binom{10}{3} 0.4^3 (1 - 0.4)^{10-3} = 120 \cdot 0.4^3 \cdot 0.6^7 \approx 0.215
\]
Given that you have \( B(7, 0.712) \) find P(3) to the nearest thousandth
\[
\underline{\hspace{3cm}}
\]
Expert Solution
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B(7, 0.712)
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