Relax! A recent survey asked 1682 people how many hours per day they were able to relax. The results are presented in the following table. Number of Hours Frequency 0 113 1 184 2 336 3 251 4 318 5 234 6 151 7 35 8 60 Total 1682 Send data to Excel Consider these 1682 people to be a population. Let X be the number of hours of relaxation for a person sampled at random from this population. Part 1 of 5 (a) Construct the probability distribution of X . Round the answer to three decimal places. x 0 1 2 3 4 5 6 7 8 P ( x ) Part 2 of 5 (b) Find the probability that a person relaxes more than 4 hours per day. The probability that a person relaxes more than 4 hours per day is .( Round the answer to three decimal places.) Part 3 of 5 (c) Find the probability that a person doesn't relax at all. The probability that a person doesn't relax at all is .( Round the answer to three decimal places.) Part 4 of 5 (d) Compute the mean μx . Round the answer to two decimal places. μx = Part 5 of 5 (e) Compute the standard deviation σx . Round the answer to three decimal places. σx =
Relax! A recent survey asked 1682 people how many hours per day they were able to relax. The results are presented in the following table. Number of Hours Frequency 0 113 1 184 2 336 3 251 4 318 5 234 6 151 7 35 8 60 Total 1682 Send data to Excel Consider these 1682 people to be a population. Let X be the number of hours of relaxation for a person sampled at random from this population. Part 1 of 5 (a) Construct the probability distribution of X . Round the answer to three decimal places. x 0 1 2 3 4 5 6 7 8 P ( x ) Part 2 of 5 (b) Find the probability that a person relaxes more than 4 hours per day. The probability that a person relaxes more than 4 hours per day is .( Round the answer to three decimal places.) Part 3 of 5 (c) Find the probability that a person doesn't relax at all. The probability that a person doesn't relax at all is .( Round the answer to three decimal places.) Part 4 of 5 (d) Compute the mean μx . Round the answer to two decimal places. μx = Part 5 of 5 (e) Compute the standard deviation σx . Round the answer to three decimal places. σx =
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
Related questions
Question
Relax! A recent survey asked
1682
people how many hours per day they were able to relax. The results are presented in the following table.
| Number of Hours | Frequency |
|
0
|
113
|
|
1
|
184
|
|
2
|
336
|
|
3
|
251
|
|
4
|
318
|
|
5
|
234
|
|
6
|
151
|
|
7
|
35
|
|
8
|
60
|
| Total |
1682
|
Send data to Excel
Consider these 1682 people to be a population. Let
X
be the number of hours of relaxation for a person sampled at random from this population.
Part 1 of 5
(a) Construct the probability distribution of
. Round the answer to three decimal places.
X
|
|
Part 2 of 5
(b) Find the probability that a person relaxes more than
hours per day.
4
|
The probability that a person relaxes more than
4
|
|
Part 3 of 5
(c) Find the probability that a person doesn't relax at all.
|
The probability that a person doesn't relax at all is
|
|
Part 4 of 5
(d) Compute the mean
. Round the answer to two decimal places.
μx
|
μx
=
|
|
Part 5 of 5
(e) Compute the standard deviation
. Round the answer to three decimal places.
σx
|
σx
=
|
|
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