Regression Statirties Muiple R R Square Practice Problem 3 0.9645 0.9303 Adjusted RSquare 0.9283 Standard Error Observations 230.5 37 The owner of an ice cream shop records the daily high temperature and daily sales for 37 days during the summer. Daily high temperatures ranged fro 100 degrees. Sales ranged from $1,824 to $4,783. Type your answers in this text box. ANOVA a. Interpret bo in the context of this problem. SgniticanceF 1 24821242.3 24821242.3 467. 1819406 7.90202E-22 AMS Regression Residual 35 1859539.95 53129.7128 Total 36 26680782.3 Ob. Interpret bi in the context of this problem. Conlicient. Standard Enor -3817.8 342.707286 88.011 4.07186316 Lower S bw 0:oww Kerper Star -11. 140038 4.67134E-13 -4513.50494 -3122 -4513.5 -3122 21614392 7.90202E-22 79.74452478 96.277 79.745 96.277 Pvale ntercept Temperature c. What percent of total variation in sales is explained by the regression model? Provide evidence to support your answer. d. Can the daily high temperature explairsales? Provide evidence to support your answer.

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The owner of an ice cream shop records the daily high temperature and daily sales for 37 days during the summer.  Daily high temperatures ranged from 63 to 100 degrees.  Sales ranged from $1,824 to $4,783.

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ТextBox 2
A
B
E
F
G
H
K
L
M
P
Q
R
Y
1
SUMMARY OUTPUT
2
Regression Statistics
0.9645
3
Practice Problem #3
4 Multiple R
5 RSquare
Adjusted RSquare 0.9283
7 Standard Error
0.9303
6
The owner of an ice cream shop records the daily high temperature and daily sales for 37 days during the summer. Daily high temperatures ranged from 63 to
7
230.5
100 degrees. Sales ranged from $1,824 to $4,783.
8
Observations
37
Type your answers in this text box.
9
10
ANOVA
a. Interpret bo in the context of this problem.
Signiticance F
1 24821242.3 24821242.3 467.1819406 7.90202E-22
11
AYS
12
Regression
13
Residual
35 1859539.95 53129.7128
14
Total
36 26680782.3
b. Interpret b1 in the context of this problem.
15
Coefficient. Standard Enor
-3817.8 342.707286
Lipper 5lower per 5
-3122
16
Stat
Pvalue
Lower
17
Intercept
-11.140038
4.67134E-13 -4513.50494
-3122 -4513.5
Temperature
88.011 4.07186316
21.614392 7.90202E-22 79.74452478 96.277 79.745
96.277
c. What percent of total variation in sales is explained by the regression model? Provide evidence to support your answer.
18
19
20
21
d. Can the daily high temperature explain sales? Provide evidence to support your answer.
22
23
24
25
e. If the daily high temperature is 87 degrees, what are the expected sales for that day?
26
27
28
Transcribed Image Text:ТextBox 2 A B E F G H K L M P Q R Y 1 SUMMARY OUTPUT 2 Regression Statistics 0.9645 3 Practice Problem #3 4 Multiple R 5 RSquare Adjusted RSquare 0.9283 7 Standard Error 0.9303 6 The owner of an ice cream shop records the daily high temperature and daily sales for 37 days during the summer. Daily high temperatures ranged from 63 to 7 230.5 100 degrees. Sales ranged from $1,824 to $4,783. 8 Observations 37 Type your answers in this text box. 9 10 ANOVA a. Interpret bo in the context of this problem. Signiticance F 1 24821242.3 24821242.3 467.1819406 7.90202E-22 11 AYS 12 Regression 13 Residual 35 1859539.95 53129.7128 14 Total 36 26680782.3 b. Interpret b1 in the context of this problem. 15 Coefficient. Standard Enor -3817.8 342.707286 Lipper 5lower per 5 -3122 16 Stat Pvalue Lower 17 Intercept -11.140038 4.67134E-13 -4513.50494 -3122 -4513.5 Temperature 88.011 4.07186316 21.614392 7.90202E-22 79.74452478 96.277 79.745 96.277 c. What percent of total variation in sales is explained by the regression model? Provide evidence to support your answer. 18 19 20 21 d. Can the daily high temperature explain sales? Provide evidence to support your answer. 22 23 24 25 e. If the daily high temperature is 87 degrees, what are the expected sales for that day? 26 27 28
Expert Solution
Step 1

Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a time so we are answering the first three as you have not mentioned which of these you are looking for. Please re-submit the question separately for the remaining sub-parts.

 

From the given excel output, 

 

Coefficient

Standard error

P-value

Intercept

-3817.8

342.707286

0.000

Temperature

88.011

4.07186316

0.000

 

The R-square is 0.9303.

Step 2

By using the given information, the regression model is:

y^=b0+b1×xSales=-3817.8+88.011×Tempertaure

 

 

From the given information,

the p-value is less than 0.05 level of significance for both the overall regression model and the independent variable (temperature). Thus, the model and variable both are statistically significant.

Step 3

3).

a).

Interpretation of b0 of a regression line,

The y-intercept of the least-squares regression means that the expected mean value of when all values of X are 0.

Thus, it can be interpreted as:

If the temperature is 0, then the predicted value of daily sales will be -3817.8.

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