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Refrigerant 134a is stored inside an uninsulated rigid tank (see figure below) and heated by an electric resistor for 5 minutes. How much energy is lost from the refrigerant through the tank walls during this process? Refer to the table below for properties Resistor R134a Refrigerant Vtank 0.01 m³ T₁ -10°C X1=0.8 T₂-40°C Battery Current 5 amp 12-Volt Battery

Refrigerant 134a is stored inside an uninsulated rigid tank (see figure below) and heated by an electric resistor for 5 minutes. How much energy is lost from the refrigerant through the tank walls during this process? Refer to the table below for properties Resistor R134a Refrigerant Vtank 0.01 m³ T₁ -10°C X1=0.8 T₂-40°C Battery Current 5 amp 12-Volt Battery

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Refrigerant 134a is stored inside an uninsulated ridged tank and heated by an electric resistor for 5 minutes. The temp goes from -10 degrees Celsius to 40 degrees Celsius. The refrigerant has a quality of .8 and the tank has a volume of .01m^3. The electrical resistor is powered by a 12V battery with a current of 5 amps. How much energy is lost from the refrigerant through the tank walls during this process.
### Educational Explanation of Refrigerant Heating Experiment **Description:** In this experiment, Refrigerant 134a is stored inside an uninsulated rigid tank and is heated by an electric resistor for 5 minutes. We aim to calculate the energy lost from the refrigerant through the tank walls during this process. **Diagram:** - **Tank with Refrigerant (R134a):** A rectangular tank is depicted containing Refrigerant 134a. An electric resistor is placed inside the tank, connected to heat the refrigerant. - **Battery:** A 12-volt battery is connected with cables leading to the resistor, providing electrical energy to it. **Table of Properties:** - **Refrigerant:** - **V_tank:** 0.01 m³ - **T1:** -10°C - **x1:** 0.8 (Quality) - **T2:** 40°C - **Battery:** - **Current:** 5 amp **Considerations:** By analyzing the given properties and setup, one can perform calculations to determine the energy loss through the tank walls. This involves understanding how electrical energy from the battery is converted into heat by the resistor and transferred to the refrigerant, raising its temperature from T1 to T2.
Transcribed Image Text:### Educational Explanation of Refrigerant Heating Experiment **Description:** In this experiment, Refrigerant 134a is stored inside an uninsulated rigid tank and is heated by an electric resistor for 5 minutes. We aim to calculate the energy lost from the refrigerant through the tank walls during this process. **Diagram:** - **Tank with Refrigerant (R134a):** A rectangular tank is depicted containing Refrigerant 134a. An electric resistor is placed inside the tank, connected to heat the refrigerant. - **Battery:** A 12-volt battery is connected with cables leading to the resistor, providing electrical energy to it. **Table of Properties:** - **Refrigerant:** - **V_tank:** 0.01 m³ - **T1:** -10°C - **x1:** 0.8 (Quality) - **T2:** 40°C - **Battery:** - **Current:** 5 amp **Considerations:** By analyzing the given properties and setup, one can perform calculations to determine the energy loss through the tank walls. This involves understanding how electrical energy from the battery is converted into heat by the resistor and transferred to the refrigerant, raising its temperature from T1 to T2.
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