Referring to the posted calibration curve ... A 154 g sample of a ruthenium ore was dissolved and diluted to 75.00 mL.  10.00 mL of this sample was removed, treated appropriately, and diluted to 250.00 mL. This solution has an absorbance of 0.840.  Calculate the percentage of ruthenium (MW = 101.07 g/mol) in the sample.

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Referring to the posted calibration curve ...

A 154 g sample of a ruthenium ore was dissolved and diluted to 75.00 mL.  10.00 mL of this sample was removed, treated appropriately, and diluted to 250.00 mL. This solution has an absorbance of 0.840.  Calculate the percentage of ruthenium (MW = 101.07 g/mol) in the sample.

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Calibration Curve to use on SEPT 27.pdf
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Calibration Curve to use for SEPT 27 and HW assignment..
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Transcribed Image Text:S Shop Trendy Women's Fas X N Calibration Curve to use o b A 0.4567 g sample of a rut X M Inbox (486) - sydmccarthy x M Inbox (530) - symccart@n x + -> i educat.nmu.edu/moodle2/pluginfile.php/613611/mod_resource/content/0/Calibration%20Curve%20to%20use%20on%20SEPT%2027.pdf Update : E Apps O Current Student Inf... N Technology Suppor.. N IT Services N My NMU O NMU EduCat™M N MyUser N NMU Library M NMU Webmail N Go to activity E Reading list >> Calibration Curve to use on SEPT 27.pdf 1 / 1 60% + Calibration Curve to use for SEPT 27 and HW assignment.. 1.2 1 0.8 1 A 0.6 0.4 0.2 0.005 0.01 0.015 0.02 0.025 0.03 0.035 (Ru), M 8:28 PM O Type here to search 61°F Clear 9/28/2021 ... II
Expert Solution
Step 1

The calibration curve given is,

Chemistry homework question answer, step 1, image 1

Given: Mass of sample used = 154 g.

Volume of original sample prepared = 75.00 mL = 0.07500 L                                                  (Since 1 L = 1000 mL)

Volume of original sample used = 10.00 mL = 0.010 L

Volume of final solution diluted to = 250.00 mL = 0.250 L

And absorbance of solution = 0.840 

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