[References] The blood alcohol (C2H5 OH) level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr+ (ag) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr207) is orange in solution, and the Cr+ ion is green. The unbalanced redox equation is Cr2O,2- (aq) + C,H; OH(aq) + Cr3+ (aq) + CO2(9) If 44.25 mL of 0.0250 M potassium dichromate solution is required to titrate 30.0 g blood plasma, determine the mass percent of alcohol in the blood. Mass percent=

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[References]
The blood alcohol (C2H5 OH) level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in
the production of Cr (ag) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr2 O72-) is orange in solution, and the
Crt ion is green. The unbalanced redox equation is
3+
Cr2O,2- (aq) + C2H5 OH(aq) → Cr** (aq) + CO2(9)
If 44.25 mL of 0.0250 M potassium dichromate solution is required to titrate 30.0 g blood plasma, determine the mass percent of alcohol in the blood.
Mass percent
%3D
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Transcribed Image Text:[References] The blood alcohol (C2H5 OH) level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr (ag) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr2 O72-) is orange in solution, and the Crt ion is green. The unbalanced redox equation is 3+ Cr2O,2- (aq) + C2H5 OH(aq) → Cr** (aq) + CO2(9) If 44.25 mL of 0.0250 M potassium dichromate solution is required to titrate 30.0 g blood plasma, determine the mass percent of alcohol in the blood. Mass percent %3D Submit Answer Try Another Version 10 item attempts remaining ot pt pt 1 pt 1 pt 1 pt 1 pt 12:53 PM 12/6/2021 to search F1 F12 INSERT DEL PAT SC
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