[References] The blood alcohol (C2H5 OH) level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr+ (ag) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr207) is orange in solution, and the Cr+ ion is green. The unbalanced redox equation is Cr2O,2- (aq) + C,H; OH(aq) + Cr3+ (aq) + CO2(9) If 44.25 mL of 0.0250 M potassium dichromate solution is required to titrate 30.0 g blood plasma, determine the mass percent of alcohol in the blood. Mass percent=
[References] The blood alcohol (C2H5 OH) level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr+ (ag) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr207) is orange in solution, and the Cr+ ion is green. The unbalanced redox equation is Cr2O,2- (aq) + C,H; OH(aq) + Cr3+ (aq) + CO2(9) If 44.25 mL of 0.0250 M potassium dichromate solution is required to titrate 30.0 g blood plasma, determine the mass percent of alcohol in the blood. Mass percent=
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![[References]
The blood alcohol (C2H5 OH) level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in
the production of Cr (ag) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr2 O72-) is orange in solution, and the
Crt ion is green. The unbalanced redox equation is
3+
Cr2O,2- (aq) + C2H5 OH(aq) → Cr** (aq) + CO2(9)
If 44.25 mL of 0.0250 M potassium dichromate solution is required to titrate 30.0 g blood plasma, determine the mass percent of alcohol in the blood.
Mass percent
%3D
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Transcribed Image Text:[References]
The blood alcohol (C2H5 OH) level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in
the production of Cr (ag) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr2 O72-) is orange in solution, and the
Crt ion is green. The unbalanced redox equation is
3+
Cr2O,2- (aq) + C2H5 OH(aq) → Cr** (aq) + CO2(9)
If 44.25 mL of 0.0250 M potassium dichromate solution is required to titrate 30.0 g blood plasma, determine the mass percent of alcohol in the blood.
Mass percent
%3D
Submit Answer
Try Another Version
10 item attempts remaining
ot
pt
pt
1 pt
1 pt
1 pt
1 pt
12:53 PM
12/6/2021
to search
F1
F12
INSERT
DEL
PAT SC
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