Question 17 **Title: Understanding Tetrahedral Intermediates in Acyl Transfer Reactions**In acyl transfer reactions (nucleophilic substitution at carbonyl), the reaction proceeds in two stages via a "tetrahedral intermediate." Here, we'll explore the formation of this intermediate through a given reaction.**Reaction Overview:**The reaction involves a compound with the structure: - A benzene ring attached to a carbonyl group (C=O) with a chlorine (Cl) substituent on the carbonyl carbon.- This is reacted with a molecule containing an amine group (NH2) and a hydroxyl group (OH).**Steps to Draw the Tetrahedral Intermediate:**1. **Identify the Reactants:** - Reactant 1: A benzene ring attached to a carbonyl group (C=O) with a chlorine (Cl) substituent on the carbonyl carbon. - Reactant 2: Molecule with an amine group (NH2) and a hydroxyl group (OH).2. **Formation of the Intermediate:** - The nucleophilic attack takes place when the amine nitrogen (NH2) attacks the carbonyl carbon (C=O) of the benzoyl chloride. 3. **After the Nucleophilic Attack:** - This attack results in the addition of the nucleophile (NH2 group) to the carbonyl carbon, breaking the double bond (C=O) and forming a single bond (C-OH). The carbon now has four single bonds, making it a tetrahedral intermediate.**Key Points:**- You do not have to consider stereochemistry.- Include all valence lone pairs in your drawing.- Do not include counter-ions like \( \text{Na}^+ \) or \( \text{I}^- \).- If more than one intermediate can be formed, just draw one.**Diagrams:**The diagram editor tools available will allow you to draw the various bonds and lone pairs needed to represent the tetrahedral intermediate accurately. - **Benzene ring structure**: Use the hexagon symbol.- **Carbonyl group (C=O)**: Draw the double bond from the hexagon (benzene) to the oxygen atom.- **Chlorine substituent**: Draw the Cl atom on the carbonyl carbon before reaction and indicate its replacement after the nucleophilic attack.- **

Answered: Image /qna-images/answer/4f033263-a965-4125-a78f-7dcc8c951b21.jpg

[References] Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. O OH + H₂N CI

[References] Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. O OH + H₂N CI

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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