(References] A 19.9-L tank is filled with H, to a pressure of 200. atm. How many balloons (each 2.00 L) can be inflated to a pressure of 1.00 atm from the tank? Assume the ideal gas behavior, that there is no temperature change, and that the tank cannot be emptied below 1.00 atm pressure. balloon(s) Submir

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A 19.9-L tank is filled with H2 to a pressure of 200. atm. How many balloons (each 2.00 L) can be inflated to a pressure of 1.00 atm from the tank? Assume the ideal gas behavior, that there is no
temperature change, and that the tank cannot be emptied below 1.00 atm pressure.
balloon(s)
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Transcribed Image Text:C X b Answered x Co. How to Ca X N NSU Logir X PeriodicTa X M Action Re X mySigTau X G 4.25 ml to x NBA Final: X G scientific X + genow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-take [References] A 19.9-L tank is filled with H2 to a pressure of 200. atm. How many balloons (each 2.00 L) can be inflated to a pressure of 1.00 atm from the tank? Assume the ideal gas behavior, that there is no temperature change, and that the tank cannot be emptied below 1.00 atm pressure. balloon(s) Submit Answer Try Another Version 3 item attempts remaining Visited Previous Next Email Instructor Save and E Cengage Learning | Cengage Technical Support
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The pressure of a fixed amount of gas changes inversely with its volume (if the temperature is constant). This statement is known as Boyle’s law (based on the experiment conducted by Robert Boyle). For a fixed amount of gas at constant temperature, let the initial volume be V1 and the pressure be p1. Let V2 and p2 be the corresponding final quantities after expansion (or contraction) of the gas. Then the Boyle’s law can be written as: 

p1V1=p2V2

Given data: 

Here p1= 200 atm V119.9 L 

 And p2= 1.00 atm V=2.00 L 

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