Reference the algorithm in the attached image. (a) Write code to implement the algorithm in python. (b) Using the list L = 60, 35, 82, 112, 9, 50 as your input, print the output of the algorithm. (c) Modify the algorithm to a. print the array Count after each iteration of i in the nested for loop (second for loop). b. include code to count the number of times the if statement is executed. c. print the S array.
Reference the algorithm in the attached image. (a) Write code to implement the algorithm in python. (b) Using the list L = 60, 35, 82, 112, 9, 50 as your input, print the output of the algorithm. (c) Modify the algorithm to a. print the array Count after each iteration of i in the nested for loop (second for loop). b. include code to count the number of times the if statement is executed. c. print the S array.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Reference the
(a) Write code to implement the algorithm in python.
(b) Using the list L = 60, 35, 82, 112, 9, 50 as your input, print the output of the
algorithm.
(c) Modify the algorithm to
a. print the array Count after each iteration of i in the nested for loop
(second for loop).
b. include code to count the number of times the if statement is executed.
c. print the S array.
![ALGORITHM Comparison Counting Sort(A[0..n-1])
//Sorts an array by comparison counting
//Input: Array A[0..n-1] of orderable values
//Output: Array S[0..n-1] of A's elements sorted
// in nondecreasing order
for i 0 ton - 1 do
Count[i] +0
for i 0 to n - 2 do
for ji+ 1 to n - 1 do
if A[i]<A[j]
Count[j] Count[j]+1
else Count[i] <Count[i] + 1
for i 0 ton - 1 do
S[Count[i]] ← A[i]
return S](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F16a501d0-ad86-4e86-a9d4-08a716d78319%2F10f18004-98ca-4454-b7e0-2dbe0fc32bda%2Fpea6xv_processed.png&w=3840&q=75)
Transcribed Image Text:ALGORITHM Comparison Counting Sort(A[0..n-1])
//Sorts an array by comparison counting
//Input: Array A[0..n-1] of orderable values
//Output: Array S[0..n-1] of A's elements sorted
// in nondecreasing order
for i 0 ton - 1 do
Count[i] +0
for i 0 to n - 2 do
for ji+ 1 to n - 1 do
if A[i]<A[j]
Count[j] Count[j]+1
else Count[i] <Count[i] + 1
for i 0 ton - 1 do
S[Count[i]] ← A[i]
return S
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