Refer to the sample tables and sample data below. Then answer questions (a), (b), (c), and (d). Tables: adult (id(pk), name, spouse_id (fk)) -- foreign key (spouse_id) references adult(id) child (id(pk), name) parent_child (parent (pk, fk), child (pk, fk)) foreign key (parent) references adult(id) -- foreign key (child) references child(id)) mysql> SELECT * FROM adult; |id|name | 1 | Homer Simpson 2 Marge Simpson 3 | Fred Flintstone 4 Wilma Flintstone | mysql> SELECT * FROM child; ---- id name **** 11 Bart 12 Lisa 13 Maggie 14 Pebbles 1| 11 21 11 1 12 12 13 i spouse_id i mysql> SELECT * FROM parent_child; I parent child | 21 11 21 3 13 14 14 4 3 | How many times will the names Bart and Homer Simpson appear in the result set from the following command? SELECT c.name, a.name FROM child c 30IN parent_child pc ON c.id pc.child JOIN adult a ON a.id = pc.parent; (a) Bart appears [Select) (b) Homer Simpson appears [Select] ✓times. times.

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Refer to the sample tables and sample data below. Then answer questions (a), (b), (c), and (d).
Tables:
adult (id(pk), name, spouse_id (fk))
-- foreign key (spouse_id) references adult(id)
child (id(pk), name)
parent_child (parent (pk, fk), child (pk, fk))
-- foreign key (parent) references adult(id)
-- foreign key (child) references child(id)
mysql> SELECT * FROM adult;
id | name
1 Homer Simpson
2 | Marge Simpson
3
Fred Flintstone
4 Wilma Flintstone |
mysql> SELECT * FROM child;
|id|name
11 Bart
12
Lisa
13
Maggie
14 Pebbles
1
2
| spouse_id
mysql> SELECT * FROM parent_child;
parent | child |
2
1
2
3 |
41
11 |
11
12
12
13
13
14
14
1
4
How many times will the names Bart and Homer Simpson appear in the result set from the following command?
SELECT c.name, a.name
FROM child c JOIN parent_child pc ON c.id = pc.child
JOIN adult a ON a.id = pc.parent;
(a) Bart appears [Select]
(b) Homer Simpson appears [Select]
times.
✓times.
Transcribed Image Text:Refer to the sample tables and sample data below. Then answer questions (a), (b), (c), and (d). Tables: adult (id(pk), name, spouse_id (fk)) -- foreign key (spouse_id) references adult(id) child (id(pk), name) parent_child (parent (pk, fk), child (pk, fk)) -- foreign key (parent) references adult(id) -- foreign key (child) references child(id) mysql> SELECT * FROM adult; id | name 1 Homer Simpson 2 | Marge Simpson 3 Fred Flintstone 4 Wilma Flintstone | mysql> SELECT * FROM child; |id|name 11 Bart 12 Lisa 13 Maggie 14 Pebbles 1 2 | spouse_id mysql> SELECT * FROM parent_child; parent | child | 2 1 2 3 | 41 11 | 11 12 12 13 13 14 14 1 4 How many times will the names Bart and Homer Simpson appear in the result set from the following command? SELECT c.name, a.name FROM child c JOIN parent_child pc ON c.id = pc.child JOIN adult a ON a.id = pc.parent; (a) Bart appears [Select] (b) Homer Simpson appears [Select] times. ✓times.
How many times will the name Marge Simpson appear in the result set from the following command?
SELECT al.name, a2.name
FROM adult al JOIN adult a2 ON al.id=a2.spouse_id;
(c) Marge Simpson appears [Select]
How many times will the name Wilma Flintstone appear in the result set from the following command?
SELECT a1.name, a2.name
FROM adult al JOIN adult a2 ON al.id = a2.spouse_id
WHERE al.id < a2.id;
times.
(d) Wilma Flintstone appears [Select]
✓times.
Transcribed Image Text:How many times will the name Marge Simpson appear in the result set from the following command? SELECT al.name, a2.name FROM adult al JOIN adult a2 ON al.id=a2.spouse_id; (c) Marge Simpson appears [Select] How many times will the name Wilma Flintstone appear in the result set from the following command? SELECT a1.name, a2.name FROM adult al JOIN adult a2 ON al.id = a2.spouse_id WHERE al.id < a2.id; times. (d) Wilma Flintstone appears [Select] ✓times.
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