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Refer to the formula below. P(x = k) = P(x = 4) = CMC-k We have previously determined N = 12, M = 6, k = 4, and n = 4. Substitute these values into the formula, or use technology. Round your final answer to four decimal places. CMC-k N-M P(x = k) = CN N-M C4 C4-412-6 C¹2 Therefore, the probability that all four plants that emerged were from treated seeds, to four decimal places, is

Refer to the formula below. P(x = k) = P(x = 4) = CMC-k We have previously determined N = 12, M = 6, k = 4, and n = 4. Substitute these values into the formula, or use technology. Round your final answer to four decimal places. CMC-k N-M P(x = k) = CN N-M C4 C4-412-6 C¹2 Therefore, the probability that all four plants that emerged were from treated seeds, to four decimal places, is

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Step 4

Step 3 Refer to the formula below for the probability of exactly k successes in a random sample of size n. N - M MCn Cn-k CAN We are asked to find the probability that there are exactly four plants from treated seeds (successes), k = 4 Step 4 Refer to the formula below. P(x = k) P(x = 4) P(x = k) = = = P(x = k) = We have previously determined N = N - M CKMCn-k N C₂₁ 6C4 CA ск - 4 12 CA ск MCn-k сп 12 6 N N - M 4, in the sample of four plants that emerged, n = 4 12, M = 6, k = 4, and n = 4. Substitute these values into the formula, or use technology. Round your final answer to four decimal places. Therefore, the probability that all four plants that emerged were from treated seeds, to four decimal places, is 4 I
Transcribed Image Text:Step 3 Refer to the formula below for the probability of exactly k successes in a random sample of size n. N - M MCn Cn-k CAN We are asked to find the probability that there are exactly four plants from treated seeds (successes), k = 4 Step 4 Refer to the formula below. P(x = k) P(x = 4) P(x = k) = = = P(x = k) = We have previously determined N = N - M CKMCn-k N C₂₁ 6C4 CA ск - 4 12 CA ск MCn-k сп 12 6 N N - M 4, in the sample of four plants that emerged, n = 4 12, M = 6, k = 4, and n = 4. Substitute these values into the formula, or use technology. Round your final answer to four decimal places. Therefore, the probability that all four plants that emerged were from treated seeds, to four decimal places, is 4 I
Tutorial Exercise Seeds are often treated with a fungicide for protection in poor-draining, wet environments. In a small-scale trial, six treated seeds and six untreated seeds were planted in clay soil and the number of plants emerging from the treated and untreated seeds were recorded. Suppose the dilution was not effective and only four plants emerged. Let x represent the number of plants that emerged from treated seeds. (a) Find the probability that x = 4. (b) Find P(x ≤ 3). (c) Find P(2 ≤ x ≤ 3). Step 1 (a) Find the probability that x = 4. n To confirm that the hypergeometric distribution is appropriate for this sample, check that ≥ 0.05, where n = 4 is the number of plants that emerged, and N = 12 is the total number of seeds planted. (Round your answer to two decimal N places.) n N = 4 12 0.33 The ratio n is 0.33 is greater than 0.05, so we can can use the hypergeometric probability distribution for this exercise. Step 2 Recall that a hypergeometric distribution population contains M successes and N M failures. We will consider a treated seed to be a success and an untreated seed to be a failure. It is given that six treated seeds and six untreated seeds were planted in clay soil. We determined in the previous step that the total number of seeds planted is N = 12. The total number of successes, or treated seeds planted, is M = 6 6
Transcribed Image Text:Tutorial Exercise Seeds are often treated with a fungicide for protection in poor-draining, wet environments. In a small-scale trial, six treated seeds and six untreated seeds were planted in clay soil and the number of plants emerging from the treated and untreated seeds were recorded. Suppose the dilution was not effective and only four plants emerged. Let x represent the number of plants that emerged from treated seeds. (a) Find the probability that x = 4. (b) Find P(x ≤ 3). (c) Find P(2 ≤ x ≤ 3). Step 1 (a) Find the probability that x = 4. n To confirm that the hypergeometric distribution is appropriate for this sample, check that ≥ 0.05, where n = 4 is the number of plants that emerged, and N = 12 is the total number of seeds planted. (Round your answer to two decimal N places.) n N = 4 12 0.33 The ratio n is 0.33 is greater than 0.05, so we can can use the hypergeometric probability distribution for this exercise. Step 2 Recall that a hypergeometric distribution population contains M successes and N M failures. We will consider a treated seed to be a success and an untreated seed to be a failure. It is given that six treated seeds and six untreated seeds were planted in clay soil. We determined in the previous step that the total number of seeds planted is N = 12. The total number of successes, or treated seeds planted, is M = 6 6
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Step 1: State the provided information.

The information provided in the question are as follows :-

T o t a l space n u m b e r space o f space o b j e c t s space left parenthesis N right parenthesis space equals space 12

S a m p l e space s i z e space left parenthesis n right parenthesis space equals space 4

N u m b e r space o f space s u c c e s s e s space i n space s a m p l e space left parenthesis k right parenthesis space equals space 4

N u m b e r space o f space s u c c e s s e s space i n space p o p u l a t i o n space left parenthesis M right parenthesis space equals space 6



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