Refer to the following line of current set up to answer each part of this question. d. (a) Assuming you chose the origin to be at the center of the wire, how would you rewrite the di vector? o (0,d1,0) o (0,dv.0) o (0,-dy.o) o (0,-y.0) (b) What is the r vector from the line of current to the observation point (labeled P)? O (r.0,0) 0 (d.y.0) o (-d.y.o) (c) What would you pick as your limits to your integral? O-L to L O-L to 0 P.
Refer to the following line of current set up to answer each part of this question. d. (a) Assuming you chose the origin to be at the center of the wire, how would you rewrite the di vector? o (0,d1,0) o (0,dv.0) o (0,-dy.o) o (0,-y.0) (b) What is the r vector from the line of current to the observation point (labeled P)? O (r.0,0) 0 (d.y.0) o (-d.y.o) (c) What would you pick as your limits to your integral? O-L to L O-L to 0 P.
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$3.temued
Refer to the following line of current set up to answer each part of this
question.
d
P
y
(a) Assuming you chose the origin to be at the center of the wire, how
would you rewrite the di vector?
(o'ip'o) o
0 (0.dy.0)
o (0,-dy.o)
o (0,-y.0)
(b) What is the r vector from the line of current to the observation point
(labeled P)?
O (r.0,0)
0 (-d.-v.o)
o (d.y.0)
o (-d.y.o)
(c) What would you pick as your limits to your integral?
-L to L
-L to 0
on -o
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