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Refer to the circuit below. Using supperposition, The current Iz is given by: R 24 1 R 120 E 48 V E, 54 V 40 OA 13 = (4+1.5) A O B. 13= (-4-1.5) A OC 3=(1.5-1.5) A O D.13= (4-4) A O E 13=(-4+1.5) A O F. 13= (4-1.5) A

Refer to the circuit below. Using supperposition, The current Iz is given by: R 24 1 R 120 E 48 V E, 54 V 40 OA 13 = (4+1.5) A O B. 13= (-4-1.5) A OC 3=(1.5-1.5) A O D.13= (4-4) A O E 13=(-4+1.5) A O F. 13= (4-1.5) A

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Quèstion 1 Refer to the circuit below. Using supperposition, The current I3 is given by: R 24 1 E 54 V R120 E 48 V R T OA 13 = (4 +1.5) A O B. 13=(-4-1.5) A OC13= (1.5-1.5) A O D. 3 = (4-4) A OE 13=(-4+1.5) A OF. 13= (4-1.5) A
Transcribed Image Text:Quèstion 1 Refer to the circuit below. Using supperposition, The current I3 is given by: R 24 1 E 54 V R120 E 48 V R T OA 13 = (4 +1.5) A O B. 13=(-4-1.5) A OC13= (1.5-1.5) A O D. 3 = (4-4) A OE 13=(-4+1.5) A OF. 13= (4-1.5) A
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