---### Sample Question and Solution on Airport Data Speeds in MbpsRefer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below.#### Given Data:- Confidence Interval (T Interval): (13.046, 22.15)- Sample Mean (\( \bar{x} \)): 17.598- Sample Standard Deviation (\( S_x \)): 16.01712719- Sample Size (\( n \)): 50---#### a. Express the confidence interval in the format that uses the "less than" symbol. Given that the original listed data use one decimal place, round the confidence interval limits accordingly.\[ \text{____ Mbps} < \mu < \text{____ Mbps} \]**(Round to one decimal place as needed.)**#### b. Identify the best point estimate of \( \mu \) and the margin of error.- **Best Point Estimate of \( \mu \)**:\[ \mu \approx \text{____ Mbps} \]- **Margin of Error (\( E \))**:\[ E = \text{____ Mbps} \]**(Round to two decimal places as needed.)**#### c. In constructing the confidence interval estimate of \( \mu \), why is it not necessary to confirm that the sample data appear to be from a population with a normal distribution?- [ ] A. Because the sample is a random sample, the distribution of sample means can be treated as a normal distribution.- [ ] B. Because the sample size of 50 is greater than 30, the distribution of sample means can be treated as a normal distribution.- [ ] C. Because the sample standard deviation is known, the normal distribution can be used to construct the confidence interval.- [ ] D. Because the population standard deviation is known, the normal distribution can be used to construct the confidence interval.---### Explanation of Accompanying Data Display:**Graph/Diagram Details:**- The data display provides the confidence interval (T interval), sample mean, sample standard deviation, and sample size.- These values are essential in statistical analysis to estimate the population mean (\( \mu \)) with a specified level of confidence.- The confidence interval is given as a range (13.046, 22.15) representing the plausible values for the population mean based on the sample data.This

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Description: ---### Sample Question and Solution on Airport Data Speeds in MbpsRefer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below.#### Given Data:- Confidence Interval (T Interva

a. Consider that µ is the population mean data speed of an airport.

Math

Statistics

Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below. Tinterval (13.046.22.15) 17.598 Sx 16 01712719 n= 50 a. Express the confidence interval in the format that uses the "less than" symbol. Given that the original listed data use one decimal place, round the confidence interval limits accordingly O Mbps

Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below. Tinterval (13.046.22.15) 17.598 Sx 16 01712719 n= 50 a. Express the confidence interval in the format that uses the "less than" symbol. Given that the original listed data use one decimal place, round the confidence interval limits accordingly O Mbps

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. The results in the screen display are based on a 95% confidence level. Write a statement that correctly interprets the confidence interval. TInterval (13.046,22.15) x = 17.598 Sx = 16.01712719 n = 50 Choose the correct answer below. O A. The limits of 13.05 Mbps and 22.15 Mbps contain the true value of the mean of the population of all data speeds at the airports. B. We have 95% confidence that the limits of 13.05 Mbps and 22.15 Mbps contain the sample mean of the data speeds at the airports. OC. We have 95% confidence that the limits of 13.05 Mbps and 22.15 Mbps contain the true value of the mean of the population of all data speeds at the airports. D. The limits of 13.05 Mbps and 22.15 Mbps contain 95% of all of the data speeds at the airports.
Use the given confidence interval to find the margin of error and the sample mean. (7.14,10.84) The sample mean is The margin of error is ... (Type an integer or a decimal.) (Type an integer or a decimal.)
7.1.13 Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 1087 and x = 540 who said "yes." Use a 90% confidence level. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) Enter your answer in the answer box and then click Check Answer. 3 parts remaining Clear All 3 F7 F8
U21T. Construct a 99% confidence interval estimate for the mean u using the given sample information. (Give your answers correct to two decimal plac n = 20, x = 16.8, and s = 2.1 |3D 15.6 X to 18 You may need to use the appropriate table in Appendix B to answer this question. Need Help? Read It Watch It Talk to a Tutor
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Use the given confidence interval to find the margin of error and the sample mean. (12.7,19.7) The sample mean is (Type an integer or a decimal.) The margin of error is (Type an integer or a decimal.)
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Determine whether the following statements are True or False: In a confidence interval (CI) for a population mean, the margin of error (MOE) is half the width of the CI. If we constructed 1000 independent 90% CI’s for a population mean µ, thenwe’d expect about 900 of them to contain µ If we increase the sample size of SRS’s, then the width of the CI’s corresponding to the SRS’s decreases, i.e., the CI’s become narrower
Find the confidence interval for a Related-Samples t-test (Ch.11), given the following info: Level of confidence = 99% Before and After scores = see table below SSD (SS of the difference scores) = 2.75 Hint: as you’re doing calculations, don’t round any numbers in your calculations to less than two decimal places, or your final answer may be too rounded for you to be able to tell which answer below is correct. Person Before X1 After X2 Difference (D = X2- X1) A 15 22 +7 B 18 23 +5 C 12 17 +5 D 17 23 +6 A. 1.90 < μD < 7.18 B. 2.53 < μD < 8.02 C. 2.95 < μD < 8.55 D. 2.01 < μD < 7.58
b Statistic TInterval Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) (13.046,22.15) X = 17.598 Sx = 16.01712719 n= 50 rses below. e Home a. Express the confidence interval in the format that uses the "less than" symbol. Given that the original listed data use one decimal place, round the confidence interval limits accordingly. uncements past due gnments Mbps < µ< Mbps see score (Round to two decimal places as needed.) dy Plan b. Identify the best point estimate of u and the margin of error. adebook 1 of 1 see score The point estimate of u is Mbps. tatCrunch (Round to two decimal places as needed.) The margin of error is E = Mbps. 1 of 1 see score eText (Round to two decimal places as needed.) Chapter Contents c. In constructing the confidence interval estimate of u, why is it not necessary to confirm that the sample data appear to be from a population with a normal 1 of oo see score distribution? Tools…
Construct the indicated confidence interval for the population mean μ. (Round results to 3 decimal places.) 1. c = 0.80, x= 325, o 17, n = 89 = 2. c = 0.95, x = 188, o 12, n = 67 = 3. Tea consumption. A researcher wants to estimate the mean tea consumption of an organization. The tea consumption in pounds for 25 randomly selected tea drinkers in the organization were gathered. Their tea consumption is listed in Table 1. Assume that o = 1.0 pounds and the tea consumption follows a normal distribution. Construct a 95% confidence for the population mean. 1.9 3.4 1.9 2.3 1.2 Table 1. Tea consumption Tea Consumption (pounds) 4.5 2.8 2.8 3.2 0.9 2.3 3.4 1.7 2.6 1.9 3.6 2.9 3.3 2.4 2.9 3.2 2.9 2.8 3.1 2.0