Refer to Table 2, test solution 3 in the procedure. At equilibrium, the concentration of the FeNCS2+ is determined to be 1.5 x 10-4 M in 10.0 mL total volume of solution. a. Calculate the number of moles of Fe3+ and SCN- added. b. Calculate the number of moles of FeSCN2+ formed. c. Calculate the number of moles of each reactant present at equilibrium. moles at equilibrium = initial moles - moles used up d. Calculate the concentrations of all species at equilibrium. e. Calculate K.
Refer to Table 2, test solution 3 in the procedure. At equilibrium, the concentration of the FeNCS2+ is determined to be 1.5 x 10-4 M in 10.0 mL total volume of solution. a. Calculate the number of moles of Fe3+ and SCN- added. b. Calculate the number of moles of FeSCN2+ formed. c. Calculate the number of moles of each reactant present at equilibrium. moles at equilibrium = initial moles - moles used up d. Calculate the concentrations of all species at equilibrium. e. Calculate K.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Refer to Table 2, test solution 3 in the procedure. At equilibrium, the concentration of the FeNCS2+ is determined to be 1.5 x 10-4 M in 10.0 mL total volume of solution.
a. Calculate the number of moles of Fe3+ and SCN- added.
b. Calculate the number of moles of FeSCN2+ formed.
c. Calculate the number of moles of each reactant present at equilibrium. moles at equilibrium = initial moles - moles used up
d. Calculate the concentrations of all species at equilibrium.
e. Calculate K.
Transcribed Image Text:B. Equilibrium Test Solutions
1. Prepare the test solutions according to Table 2 using small beakers.
Table 2
Test Solution
Vol. of 0.002 M
Vol. of 0.002 M
Vol. of 0.1 M
Absorbance at
Fe(NO3)3 (mL)
NaSCN (mL)
HNO3 (mL)
447 nm
1
1
4
3
3
3
2 T
4
4
1
2. Measure the absorbance of each solution at 447 nm.
5
2.
5
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