Refer to figure 1. A wooden block stands motionless on a ramp.. Calculate the coefficier of static friction ( µs ). Refer to the table below. What could be the physical composition the ramp? Material 1 Material 2 Wood
Refer to figure 1. A wooden block stands motionless on a ramp.. Calculate the coefficier of static friction ( µs ). Refer to the table below. What could be the physical composition the ramp? Material 1 Material 2 Wood
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![**Educational Content on Friction and Motion**
1. **Understanding Static Friction on an Inclined Plane**
Refer to Figure 1. A wooden block stands motionless on a ramp inclined at 31.8 degrees. This situation involves static friction which prevents the block from sliding down. To determine the coefficient of static friction (\(\mu_s\)), we utilize the following table that lists the coefficients for various material pairings:
| **Material 1** | **Material 2** | **\(\mu\)** |
|----------------|---------------------|-------------|
| Wood | Wood (clean) | 0.25 - 0.5 |
| Wood | Wood (wet) | 0.2 |
| Wood | Concrete | 0.62 |
| Wood | Brick | 0.6 |
The angle of the ramp allows us to infer that the coefficient of static friction is around the tangent of the angle of inclination (\(\mu_s = \tan(\theta)\)). For \(\theta = 31.8^\circ\):
\[
\mu_s = \tan(31.8^\circ) \approx 0.62
\]
Therefore, the physical composition of the ramp can be deduced to be wood on concrete based on the provided options.
Figure 1: Illustration of a block (orange) on a ramp inclined at 31.8 degrees.
2. **Determining Kinetic Friction and Motion**
Refer to Figure 2. A block slides down a ramp inclined at 15.7 degrees at a constant speed of 12.0 m/s. This setup involves kinetic friction (\(\mu_k\)). The constant speed indicates that the forces are balanced, and thus:
\[
\mu_k = \tan(15.7^\circ) \approx 0.28
\]
To find how far the block will travel in 5.0 seconds, we use the formula for distance traveled at constant speed:
\[
\text{Distance} = \text{Speed} \times \text{Time} = 12.0 \, \text{m/s} \times 5.0 \, \text{s} = 60.0 \, \text{m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb17382d2-9e6c-40e2-a6b7-8172ebf93e2c%2Fb772d1a5-e91b-43fd-b55d-af79748ee410%2Fsf3ft8w.jpeg&w=3840&q=75)
Transcribed Image Text:**Educational Content on Friction and Motion**
1. **Understanding Static Friction on an Inclined Plane**
Refer to Figure 1. A wooden block stands motionless on a ramp inclined at 31.8 degrees. This situation involves static friction which prevents the block from sliding down. To determine the coefficient of static friction (\(\mu_s\)), we utilize the following table that lists the coefficients for various material pairings:
| **Material 1** | **Material 2** | **\(\mu\)** |
|----------------|---------------------|-------------|
| Wood | Wood (clean) | 0.25 - 0.5 |
| Wood | Wood (wet) | 0.2 |
| Wood | Concrete | 0.62 |
| Wood | Brick | 0.6 |
The angle of the ramp allows us to infer that the coefficient of static friction is around the tangent of the angle of inclination (\(\mu_s = \tan(\theta)\)). For \(\theta = 31.8^\circ\):
\[
\mu_s = \tan(31.8^\circ) \approx 0.62
\]
Therefore, the physical composition of the ramp can be deduced to be wood on concrete based on the provided options.
Figure 1: Illustration of a block (orange) on a ramp inclined at 31.8 degrees.
2. **Determining Kinetic Friction and Motion**
Refer to Figure 2. A block slides down a ramp inclined at 15.7 degrees at a constant speed of 12.0 m/s. This setup involves kinetic friction (\(\mu_k\)). The constant speed indicates that the forces are balanced, and thus:
\[
\mu_k = \tan(15.7^\circ) \approx 0.28
\]
To find how far the block will travel in 5.0 seconds, we use the formula for distance traveled at constant speed:
\[
\text{Distance} = \text{Speed} \times \text{Time} = 12.0 \, \text{m/s} \times 5.0 \, \text{s} = 60.0 \, \text{m
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