Refer the truss as shown in the figure (not scale). E,2A E,A E,A Е, А E,A P. E,A E,A L If load, F = 103 kN, moment of inertia, I = 8.33 x 106 mm4, area of cross-section A = 104 mm2, and length, L 2m for all the members of the truss, the compressive stress (in kN/m2, in integer) carried by the member Q-R is %3D

Q: analyze the shown truss using: 1- force method 2-stiffness method assume point C is roller support…

A: Truss Analysis: Force Method vs. Stiffness MethodWe'll analyze the given truss with a roller support…

Q: Given the truss and loading shown below, determine the stress at member Al if Pu = 18.375 Kips and…

A:

Q: Draw Mohr’s circle and determine the principal stresses.

A: Given Data: The stress acting along X-direction is σx=30 MPa (Tensile). The stress acting along…

Q: Consider the truss shown in (Figure 1). Suppose that F = 10 kN. Figure 3 m 4 KN 5KN kN H B C D E F…

A: Determine the force in members CD, CJ and JK of the truss.

Q: analyze the shown truss using: 1- force method 2-stiffness method assume point C is roller support…

A: ## Truss Analysis: 1-Force Method (Method of Joints)**Given:*** Point C is a roller support (resists…

Q: The members of the truss shown have identical cross- 3P sectional area of 200 mm². Determine the…

A: Allowable stress = 40 MPa = 40 N/mm2 Allowable axial displacement = 0.1 mm  E = 70 GPa = 70 × 103…

Q: Two steel plates are welded together to form an inverted T-beam and are loaded as shown below.…

A: We know that Bending stress is given by σ = MI*y For Maximum bending stress we can write  σmax =…

Q: 17.17 Member BC of the pin-connected truss has a cross sec- oy = 42 ksi. tion as shown. E = 29 x 10³…

A: Given: E=29000 ksify=42 ksi For 2 C10×30, A=17.64 in2rx=3.43 inry=1.32 in To determine: Load P.

Q: Q2: The truss shown is supported by a pins at A and G, and subjected to discrete loads as shown in…

A: Given data in question  Point loads acting at joints Span member length  To find out Reaction forces…

Q: F = 3.3 kN, a = 2.4 m, b 3 m, c= 2 m, and d = 2 m.

A:

Q: . Assume that axial eformation of Member EF is aused mainly by its reaction external forces on the…

A:

Q: Three plates are welded together to form the section shown. Dimensions of the cross section are b =…

A: Given: The value of b is 3.6 in. The value of d is 10.8 in. The value of a is 2.3 in. The value of t…

Q: 1. Assume that axial deformation of Member DF is caused mainly by its reaction to external forces on…

A:

Q: "roblem 6.40 Consider the truss shown in (Figure 1). Suppose that F₁ = 4.5 kN and F₂ = 5 kN. Figure…

A: Given : To Find : 1 Fcd 2 Fcf 3 Fcg

Q: The truss is subjected to the loading shown. It is supported by a pin at A and a roller at L.…

A:

Q: The cross-sectional area of each member of the truss is 1.6 in2. Calculate the average normal…

A: Take moment about F :∑ MF=0Ay24-308=0Ay=10kips

Mechanics of Solids

It is the study of the behavior of solid materials, their characteristics under various circumstances such as variation in external forces, temperature, and other internal factors. It is one of most important study in the field of engineering science, especially chemistry and mechanical engineering. In rigid body, the idealization of the solid body in which deformation is neglected. Deformation is known as the force acting on the solid state system which exerts change in its shape of the body but it continues to be at rest or in a uniform motion but it cannot accelerate. But those solid systems do have elasticity, compressibility and can be bent. This field is very vast since there are wide range of materials around us.