Reduction In organic chemistry, reduction is defined as a reaction in which a carbon atom forms fewer bonds to oxygen, O, or more bonds to hydrogen, H. OH HC-C-CH3 + [H] →> H3C-C-CH3 H propanone 2-propanol Practice Problems; Draw and name the product of each reduction. (d) CH2=CH2+ [H] → (e) 3-pentanone + [H] → (f) CH3CH2C=CH + [H] → (i) + [H] → (ii) (g) 2-ethyl-3,4-dimethyloctanal + [H] →
Reduction In organic chemistry, reduction is defined as a reaction in which a carbon atom forms fewer bonds to oxygen, O, or more bonds to hydrogen, H. OH HC-C-CH3 + [H] →> H3C-C-CH3 H propanone 2-propanol Practice Problems; Draw and name the product of each reduction. (d) CH2=CH2+ [H] → (e) 3-pentanone + [H] → (f) CH3CH2C=CH + [H] → (i) + [H] → (ii) (g) 2-ethyl-3,4-dimethyloctanal + [H] →
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Reduction
In organic chemistry, reduction is defined as a reaction in which a carbon atom forms
fewer bonds to oxygen, O, or more bonds to hydrogen, H.
OH
H3C-C-CH3 + [H] →>>>
H3C-C-CH3
H
propanone
2-propanol
Practice Problems;
Draw and name the product of each reduction.
→>
(d) CH2=CH2 + [H] −
(e) 3-pentanone + [H] -
→>
(f) CH3CH2C=CH + [H] → (i) + [H] → (ii)
(g) 2-ethyl-3,4-dimethyloctanal + [H] →](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F84d55fd4-413e-4455-9813-4797bba15d3a%2F6c1cafad-1ff1-437e-b16d-36c9275e0725%2Fy8zhjuq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Reduction
In organic chemistry, reduction is defined as a reaction in which a carbon atom forms
fewer bonds to oxygen, O, or more bonds to hydrogen, H.
OH
H3C-C-CH3 + [H] →>>>
H3C-C-CH3
H
propanone
2-propanol
Practice Problems;
Draw and name the product of each reduction.
→>
(d) CH2=CH2 + [H] −
(e) 3-pentanone + [H] -
→>
(f) CH3CH2C=CH + [H] → (i) + [H] → (ii)
(g) 2-ethyl-3,4-dimethyloctanal + [H] →
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