Reduce the following À expression to normal form. Show each reduction step. If already in normal form, write "normal form". Hint: you may need to perform a-conversion during the evaluation. (Ax.(Ay.(x y))) y
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- Input Output Explanation 4 11 There are 4 test cases without round 1+2*3+4 1000000006 brackets. 1*2-3 123 • Case 1: It is straightforward to evaluate that 1+2 x 3 +4 = 123 invalid +-* 11. • Case 2:1 x 2 – 3 = -1. In modular arithmetic, -1 is 1 000 000 006 (mod 1 000 000 007). • Case 3: By definition E → integer. Therefore 123 evaluates to 123. • Case 4: Each operator must have operands. This expression is invalid. 4 9 There are 4 test cases with round (1+2)*3 invalid brackets. () invalid () 100 (((1))) • Case 1: It is straightforward to evaluate that (1+ 2) × 3 = 9. • Case 2: Empty brackets are not 1 allowed by definition. • Case 3: Not only empty brackets are disallowed, but also there misses an operator between () and 100. • Case 4: By definition E (E). Therefore E → (E) → ((E)) → (((E))) → (((1))), which evaluates to 1.you are missing the zero,running and stopped boolean expression. Please check the above solution.Find the value of the Bresenham's circle drawing method's decision parameter p. Step-by-step instructions are given for how Bresenham's method for making a circle works.
- Create functional tests where arguments are given, use a parameterized test. testSimpleInit(size): the first constructor works as expected. getTiles shows suitable values. The edges of the board (the smallest and biggest conceivable values) are accessible and contain the values that they have to (BASE_TILE_SCORE). testCustomInit(x, y, expected): the second constructor works as expected. On positions where values smaller than three were passed, the board contains the value BASE_TILE_SCORE. If you pass an array to the constructor and later modify a value in it, the respective tile retains the originally passed value. If you modify an element in the return value of getTiles(), and get the value of the respective tile again, this newly received content has to be the originally set value. testMoves(): take four or five steps and check that the board’s contents are changed just right. Include a step that tries to move to the x coordinate Integer.MIN_VALUE and another one that moves to…For this discussion, we are going to be working with operators. Below is the code for the Operators class, which contains a main() method and a divisible() method. Study the code below, paying special attention to the four if statements. First, explain using complete sentences how each if statement evaluates (true or false), as well as what takes place in each if statement's test (comparisons, function calls, increments/decrements, etc.). Then, provide what the program will output. public class Operators { public static void main(String[] args) { int a = 5, b = 10, c = 11; System.out.println("This program works with operators."); if (a < 10 ^ b == 10) System.out.println("Java "); if (divisible(b, a) | divisible(c, a)) System.out.println("Programming "); if (a + b - (++c) == c - (b--) + 1) System.out.println("CITC ");…kindly change the program following the procedure on the problem. please list the changes you have made on the program t..thank you
- Task 03: Read the concept of Binomial coefficient given in chapter-6. Write a method that takes two parameters n and k and returns the value of Binomial Coefficient C(n, k). For example, your function should return 20 for n = 6 and k = 3, and it should return 35 for n= 7 and k = 4. ( confirm it through the Pascal's triangle as given below). 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 15 10 10 5 1 15 (20) 15 6 1 1 7 21 35 (35 21 7 1 1When the robot makes a turn, it would be useful to have an operation to perform on d to represent this turn. This is because after making a turn, the new value of d will depend on the old value of d. Complete the table for the new values of d if the robot is turning left or right.Then determine an expression in terms of d that will give the new position if the robot turns left and another expression if the robot turns right. Type these expressions in the last row of the table. Attached is the table I completed. All rows are correct except the last one. I'm not sure what my error is.White-box testing is defined as. Is it required to do white-box tests?
- please don't use the answer from another website. will give like!!!When an operator is met in the postfix expression evaluation example, the two most recent operands are popped so that the subexpression may be evaluated. The first popped operand is handled as the second operand in the subexpression, whereas the second popped operand is the first. Give and explain an example of how this component of the solution is important.Don't put up wrong answer. I already got wrong answer of this question. Do code attach screenshot of code so that it will help me to understand