Redo the third problem of the Prelaboratory Assignment, substituting NaIO3 (sodium iodate) for NaOCl. The new reaction yields I2 as the only product containing a halogen. 3.A 10.0-mL sample of aqueous NaOCI is treated with excess KI in an acidic solution. The quantityof iodine that is liberated is such that 28.02 mL of 0.0250 M Na₂S₂O3 solution must be added tocause the disappearance of the dark blue color due to the starch indicator. What is the molarity ofthe solution of NaOCI?# of moles of Na2S203 = M*V= 0.0250 M * 28.02mL = 0.7005mmol2. According to the balanced equation2 moles of $203 2- reacts with 1 mole of CIO-so 0.7005mmol of $203 2- reacts with 0.7005 mmol * 1/2 = 0.35025 mmol of CIO-# of moles of NaOCI= 0.35025 mmolvolume = 10mlMolarity of NaOCI=0.35025 mmol/ 10.0ml = 0.0350 M The Strength of a Laundry BleachPrelaboratory AssignmentWrite the balanced equations for the following oxidation-reduction reactions that you willencounter in this experiment:The reduction of CIO by I in acidic solution1.2.a.C1012H₂0+21Iz+CI+H₂Ob.The reduction of I₂ by S₂O3 in acidic solution2-1₂+ 25 ₂0²² → 21+ SadWhat conversion factor will enable you to calculate the number of moles of ClO ions from thenumber of moles of S₂O3 ions used in the titration?2-2 moles of $₂03 = 1 mole ofCIÓ

Reduction of ClO- by I- in an acidic medium ClO- + 2I- + 2H+ →I2 + Cl- + H2O Reduction of I2 by…

Answered: A 10.0-ml sample of aqueous NaOCI is…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Question

Redo the third problem of the Prelaboratory Assignment, substituting NaIO3 (sodium iodate) for NaOCl. The new reaction yields I2 as the only product containing a halogen.

3.
A 10.0-mL sample of aqueous NaOCI is treated with excess KI in an acidic solution. The quantity
of iodine that is liberated is such that 28.02 mL of 0.0250 M Na₂S₂O3 solution must be added to
cause the disappearance of the dark blue color due to the starch indicator. What is the molarity of
the solution of NaOCI?
# of moles of Na2S203 = M*V= 0.0250 M * 28.02mL = 0.7005mmol
2. According to the balanced equation
2 moles of $203 2- reacts with 1 mole of CIO-
so 0.7005mmol of $203 2- reacts with 0.7005 mmol * 1/2 = 0.35025 mmol of CIO-
# of moles of NaOCI= 0.35025 mmol
volume = 10ml
Molarity of NaOCI=0.35025 mmol/ 10.0ml = 0.0350 M

The Strength of a Laundry Bleach
Prelaboratory Assignment
Write the balanced equations for the following oxidation-reduction reactions that you will
encounter in this experiment:
The reduction of CIO by I in acidic solution
1.
2.
a.
C1012H₂0+21Iz+CI+H₂O
b.
The reduction of I₂ by S₂O3 in acidic solution
2-
1₂+ 25 ₂0²² → 21+ Sad
What conversion factor will enable you to calculate the number of moles of ClO ions from the
number of moles of S₂O3 ions used in the titration?
2-
2 moles of $₂03 = 1 mole of
CIÓ

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Follow-up Questions

Read through expert solutions to related follow-up questions below.

Follow-up Question

Redo the third problem of the Prelaboratory Assignment, substituting NaIO3 (sodium iodate) for NaOCl. The new reaction yields I2 as the only product containing a halogen?

Solution

by Bartleby Expert

SEE SOLUTION

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions