Redo Exercise 238 from Section 1.4, but instead of a weather satellite with a mass of 1400 kg, calculate how many Joules of work it would take to elevate an almond with a mass of 0.0012 kg to the same altitude. Enter your answer as just a number (no units), rounded to two significant digits (remember, that's not the same as two decimal places!)
Stellar evolution
We may see thousands of stars in the dark sky. Our universe consists of billions of stars. Stars may appear tiny to us but they are huge balls of gasses. Sun is a star of average size. Some stars are even a thousand times larger than the sun. The stars do not exist forever they have a certain lifetime. The life span of the sun is about 10 billion years. The star undergoes various changes during its lifetime, this process is called stellar evolution. The structure of the sun-like star is shown below.
Red Shift
It is an astronomical phenomenon. In this phenomenon, increase in wavelength with corresponding decrease in photon energy and frequency of radiation of light. It is the displacement of spectrum of any kind of astronomical object to the longer wavelengths (red) side.



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