Rectangular Snip Identify ALL of the following statements that are true in the diagram if ACAB is a scalene triangle. (1 point) в O A. sin(B) = cos(a) O B. tan(B) = tan(a) %3D O C. cos (B) = sin (a) O D. cos(B) = sin(90 – a) A b A
Rectangular Snip Identify ALL of the following statements that are true in the diagram if ACAB is a scalene triangle. (1 point) в O A. sin(B) = cos(a) O B. tan(B) = tan(a) %3D O C. cos (B) = sin (a) O D. cos(B) = sin(90 – a) A b A
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Transcribed Image Text:### Identifying True Statements in a Scalene Triangle
Consider the right-angled triangle \( \Delta CAB \) shown in the diagram. For this triangle:
- \( \angle CAB \) is represented by \( \alpha \)
- \( \angle CBA \) (the right angle)
- \( \angle ADB \) is represented by \( \beta \)
The triangle has sides labeled as follows:
- Side \( a \) opposite angle \( \alpha \)
- Side \( b \) adjacent to angle \( \alpha \)
- Hypotenuse \( c \)
### Problem Statement
Identify ALL of the following statements that are true in the given \( \Delta CAB \) where \( \alpha + \beta = 90^\circ \): (1 point)
- **A.** \( \sin(\beta) = \cos(\alpha) \)
- **B.** \( \tan(\beta) = \tan(\alpha) \)
- **C.** \( \cos(\beta) = \sin(\alpha) \)
- **D.** \( \cos(\beta) = \sin(90^\circ - \alpha) \)
**Answer Options:**
- ☐ A
- ☐ B
- ☐ C
- ☐ D
### Diagram Explanation
The diagram provided is a right-angled triangle labeled \( \Delta CAB \):
- \( \angle CBA = 90^\circ \)
- \( \angle CAB = \alpha \)
- \( \angle ADB = \beta \)
- Side opposite \( \alpha \) is \( a \)
- Side adjacent to \( \alpha \) is \( b \)
- Hypotenuse is \( c \)
### Analysis of Statements
- **Statement A:** \( \sin(\beta) = \cos(\alpha) \)
- By trigonometric identity in a right triangle, this is true because \( \beta = 90^\circ - \alpha \). Therefore, \( \sin(\beta) = \sin(90^\circ - \alpha) = \cos(\alpha) \).
- **Statement B:** \( \tan(\beta) = \tan(\alpha) \)
- This is false. \( \tan(\beta) = \tan(90^\circ - \alpha) = \cot(\alpha) \). Therefore, \( \tan(\beta) \neq \tan(\alpha)
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