Records indicate that the average weight of adult rainbow trout in Eagle Creek is 1.70 kgwith a standard deviation of0.38 kg.After years of marked oxygen depletion due to pollutants in the stream, a biologist wants to see if the standard deviation, o,of pesos has changed. The biologist measures the weights of 18 randomly selected adult rainbow trout from the stream and finds that the sample standard deviation is0.50 kg.Assume that the current weights of adult rainbow trout in the stream follow a normal distribution. Does the biologist have sufficient evidence to conclude that the population standard deviation, o, differs from0.38 kg?To answer, complete the parts below to perform a hypothesis test. Use the significance level of0.10. (a) Formulate the null hypothesish and the alternative hypothesish What would you use to perform the test? ho: 0 O 0<0 S OSO O

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 13PPS
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Question
●
The value of the test statistic is given byx²
Chi-square distribution
Step 1: Enter the number of degrees
of freedom.
Step 2: Select one queue or two
queues.
A tail
two tails
Step 3: Enter the critical value(s).
(Round to 3 decimal places.
Step 4: Enter the test statistic.
(Round to 3 decimal places.
0.3 +
0.2 +
0.1+
(no 1)yes
0²
10
fifteen
twenty
25
30
35
Transcribed Image Text:● The value of the test statistic is given byx² Chi-square distribution Step 1: Enter the number of degrees of freedom. Step 2: Select one queue or two queues. A tail two tails Step 3: Enter the critical value(s). (Round to 3 decimal places. Step 4: Enter the test statistic. (Round to 3 decimal places. 0.3 + 0.2 + 0.1+ (no 1)yes 0² 10 fifteen twenty 25 30 35
Records indicate that the average weight of adult rainbow trout in Eagle Creek is1.70 kgwith a standard deviation of0.38 kg.After years of marked oxygen
depletion due to pollutants in the stream, a biologist wants to see if the standard deviation, o,of pesos has changed. The biologist measures the weights of 18
randomly selected adult rainbow trout from the stream and finds that the sample standard deviation is0.50 kg. Assume that the current weights of adult rainbow
trout in the stream follow a normal distribution.
Does the biologist have sufficient evidence to conclude that the population standard deviation, o,differs from0.38 kg?To answer, complete the parts below to
perform a hypothesis test. Use the significance level of0.10.
(a) Formulate the null hypothesish and the alternative hypothesish What would you use to perform the test?
1
ho:
0:
h
1:
0
●
O S
0<0
OSO
□<ロ
0=0 ☐#0
(b) Perform a chi-square test. This is information that will help you perform the test.
2
2
X0.95 is the value that delimits an area of0.05 in the left tail of the distribution, and%0.05 is the value that delimits an area of 0.05 in the right tail of
the distribution.
Transcribed Image Text:Records indicate that the average weight of adult rainbow trout in Eagle Creek is1.70 kgwith a standard deviation of0.38 kg.After years of marked oxygen depletion due to pollutants in the stream, a biologist wants to see if the standard deviation, o,of pesos has changed. The biologist measures the weights of 18 randomly selected adult rainbow trout from the stream and finds that the sample standard deviation is0.50 kg. Assume that the current weights of adult rainbow trout in the stream follow a normal distribution. Does the biologist have sufficient evidence to conclude that the population standard deviation, o,differs from0.38 kg?To answer, complete the parts below to perform a hypothesis test. Use the significance level of0.10. (a) Formulate the null hypothesish and the alternative hypothesish What would you use to perform the test? 1 ho: 0: h 1: 0 ● O S 0<0 OSO □<ロ 0=0 ☐#0 (b) Perform a chi-square test. This is information that will help you perform the test. 2 2 X0.95 is the value that delimits an area of0.05 in the left tail of the distribution, and%0.05 is the value that delimits an area of 0.05 in the right tail of the distribution.
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