Recall that the work WW done by a constant force F⃗ F→ at an angle θθ to the displacement Δr⃗ Δr→ isW=F⃗ ⋅Δr⃗ =FΔrcosθW=F→⋅Δr→=FΔrcos⁡θ.The vector magnitudes FF and ΔrΔr are always positive, so the sign of WW is determined entirely by the angle θθ between the force and the displacement.What is the work WnWn done on the box by the normal force?Express your answers in joules to two significant figuresWhat is the work WTWT done by the tension force?Express your answers in joules to two significant figures. I Review ConstantLearning Goal:CorrectTo practice Tactics Box 9.1 Calculating the Work Done by aConstant Force.The component of the gravitational force parallel to the displacement does positive work and transfers energy to the system.Recall that the work W done by a constant force F at an angle 0to the displacement Ar isW = F. Ar = FAr cos 0.Part BThe vector magnitudes F and Ar are always positive, so thesign of W is determined entirely by the angle 0 between the forceand the displacement.What is the work Wn done on the box by the normal force?Express your answers in joules to two significant figures.• View Available Hint(s)?Wn =J%3DSubmitPart CWhat is the work WT done by the tension force?Express your answers in joules to two significant figures.Figure1 of 1• View Available Hint(s)?WT =J%3DSubmitProvide FeedbackNext

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Description: Recall that the work WW done by a constant force F⃗ F→ at an angle θθ to the displacement Δr⃗ Δr→ isW=F⃗ ⋅Δr⃗ =FΔrcosθW=F→⋅Δr→=FΔrcos⁡θ.The vector magnitudes FF and ΔrΔr are always positive, so the sign of WW is determined entirely by the angle θθ be

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Recall that the work WW done by a constant force F⃗ F→ at an angle θθ to the displacement Δr⃗ Δr→ is

W=F⃗ ⋅Δr⃗ =FΔrcosθW=F→⋅Δr→=FΔrcos⁡θ.

The vector magnitudes FF and ΔrΔr are always positive, so the sign of WW is determined entirely by the angle θθ between the force and the displacement.

What is the work WnWn done on the box by the normal force?

Express your answers in joules to two significant figures

What is the work WTWT done by the tension force?

Express your answers in joules to two significant figures.

I Review Constant
Learning Goal:
Correct
To practice Tactics Box 9.1 Calculating the Work Done by a
Constant Force.
The component of the gravitational force parallel to the displacement does positive work and transfers energy to the system.
Recall that the work W done by a constant force F at an angle 0
to the displacement Ar is
W = F. Ar = FAr cos 0.
Part B
The vector magnitudes F and Ar are always positive, so the
sign of W is determined entirely by the angle 0 between the force
and the displacement.
What is the work Wn done on the box by the normal force?
Express your answers in joules to two significant figures.
• View Available Hint(s)
?
Wn =
J
%3D
Submit
Part C
What is the work WT done by the tension force?
Express your answers in joules to two significant figures.
Figure
1 of 1
• View Available Hint(s)
?
WT =
J
%3D
Submit
Provide Feedback
Next

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