Recall that for a two-tailed test, the rejection region is t > ta/2 or t < -ta/2: We determined t = 1.510 in the previous step, which we will compare to the critical values ta/2 and -ta/2. For the given significance level of a = 0.05, we have ta/2= 0.05/2 = 0.025 Find to.025, the value of t with a tail area of 0.025 under the curve to the right, and n - 1 = 4 degrees of freedom. Round your answer to three decimal places. 0.025 Therefore, the rejection region is t > and t <
Recall that for a two-tailed test, the rejection region is t > ta/2 or t < -ta/2: We determined t = 1.510 in the previous step, which we will compare to the critical values ta/2 and -ta/2. For the given significance level of a = 0.05, we have ta/2= 0.05/2 = 0.025 Find to.025, the value of t with a tail area of 0.025 under the curve to the right, and n - 1 = 4 degrees of freedom. Round your answer to three decimal places. 0.025 Therefore, the rejection region is t > and t <
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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![Recall that for a two-tailed test, the rejection region is \( t > t_{\alpha/2} \) or \( t < -t_{\alpha/2} \). We determined \( t = 1.510 \) in the previous step, which we will compare to the critical values \( t_{\alpha/2} \) and \(-t_{\alpha/2} \). For the given significance level of \(\alpha = 0.05\), we have \( t_{\alpha/2} = t_{0.05/2} = t_{0.025} \).
Find \( t_{0.025} \), the value of \( t \) with a tail area of 0.025 under the curve to the right, and \( n - 1 = 4 \) degrees of freedom. Round your answer to three decimal places.
\[ t_{0.025} = \boxed{\phantom{x}} \]
Therefore, the rejection region is \( t > \boxed{\phantom{x}} \) and \( t < \boxed{\phantom{x}} \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F675d7c68-68c2-40f4-bb09-6fc638745853%2Fd2ba6156-364a-4bbd-96dc-983fc0f3dffd%2F3nuz6im_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Recall that for a two-tailed test, the rejection region is \( t > t_{\alpha/2} \) or \( t < -t_{\alpha/2} \). We determined \( t = 1.510 \) in the previous step, which we will compare to the critical values \( t_{\alpha/2} \) and \(-t_{\alpha/2} \). For the given significance level of \(\alpha = 0.05\), we have \( t_{\alpha/2} = t_{0.05/2} = t_{0.025} \).
Find \( t_{0.025} \), the value of \( t \) with a tail area of 0.025 under the curve to the right, and \( n - 1 = 4 \) degrees of freedom. Round your answer to three decimal places.
\[ t_{0.025} = \boxed{\phantom{x}} \]
Therefore, the rejection region is \( t > \boxed{\phantom{x}} \) and \( t < \boxed{\phantom{x}} \).
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