Question with last attempt is displayed for your review onlyRecall that f is the function that accepts values of h, the drop height in yards, and g is the function that accepts valuesof d, the drop height in feet. Both functions return the time it takes for a rock to hit the ground when dropped from thegiven height.j. Which function (f or g) requires a larger magnitude input value to represent the same number of seconds for therock to hit the ground?function gk. Complete cach of the following statements. 7hink carefully about what each expression represents and how torepresent the same quantity value with the other function.i. g() f(60)ii. g(33) f(66%3!iii. f(L)= 9(66)Box 1: Select the best answerBox 2: Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2 3, S+4)Enter DNE for Does Not Exist, oo for InfinityBox 3: Enter your answer as a number (like 5,-3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)Enter DNE for Does Not Exist, oo for InfinityBox 4: Enter your answer as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 2^3, 5+4)

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Description: Question with last attempt is displayed for your review onlyRecall that f is the function that accepts values of h, the drop height in yards, and g is the function that accepts valuesof d, the drop height in feet. Both functions return the time it t

Answered: Recall that f is the function that…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Step 1

GIVEN :

Function f accepts the input in yards.

Function g accepts the input in feet.

We know that :

1 yard = 3 feet.

PART j

Function g will require a larger magnitude input value because the input in feet is 3 times the input in yards.

CONCLUSION :

Function g is the answer.

Step 2

PART k

FIRST PART

Given that $g () = f (60)$

Here 60 is in yards. Therefore in g it will be $60 \times 3 = 180 f e e t$

Therefore, g(180) = f(60)

SECOND PART

Given that $g (33) = f ()$

Here 33 is in feet. Therefore in f it will be $33 \div 3 = 11 y a r d s$

Therefore, g(33) = f(11)

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