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Recall that a binomial made up of the difference of two perfect squares can be factored by the following pattern. a²b² = (a + b)(a - b) Use this pattern to factor the binomial (7b)² - 8². (76)²-8²=

Recall that a binomial made up of the difference of two perfect squares can be factored by the following pattern. a²b² = (a + b)(a - b) Use this pattern to factor the binomial (7b)² - 8². (76)²-8²=

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Recall that a binomial made up of the difference of two perfect squares can be factored by the following pattern. a²b² = (a + b)(a - b) Use this pattern to factor the binomial (76)² - 8². (7b)²-8²=
Transcribed Image Text:Recall that a binomial made up of the difference of two perfect squares can be factored by the following pattern. a²b² = (a + b)(a - b) Use this pattern to factor the binomial (76)² - 8². (7b)²-8²=
Step 3 Recall that a binomial made up of the difference of two perfect cubes can be factored by the pattern a³ b³ = (a - b)(a² + ab + 6²). Comparing the given polynomial (3d)³ – (4)³ to the pattern a³ - b³, we have a = b = and
Transcribed Image Text:Step 3 Recall that a binomial made up of the difference of two perfect cubes can be factored by the pattern a³ b³ = (a - b)(a² + ab + 6²). Comparing the given polynomial (3d)³ – (4)³ to the pattern a³ - b³, we have a = b = and
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