Reasons Statements 1. Congruent circles OP and 00; chord AB is on both circles 1. [ Select ] 2. PA, PB, OA, and OB are radii of the 2. By the construction of the radius/ circles. definition of radius 3. PA PB 3. [ Select ] OA OB 4. Point P is equidistant from points A and B. [ Select ] 4. Point O is equidistant from points A and B. 5. Point P and Point O lie on the 5. [ Select ] perpendicular bisector of AB. 6. PO is the perpendicular bisector of AB. 6. [ Select ]
Reasons Statements 1. Congruent circles OP and 00; chord AB is on both circles 1. [ Select ] 2. PA, PB, OA, and OB are radii of the 2. By the construction of the radius/ circles. definition of radius 3. PA PB 3. [ Select ] OA OB 4. Point P is equidistant from points A and B. [ Select ] 4. Point O is equidistant from points A and B. 5. Point P and Point O lie on the 5. [ Select ] perpendicular bisector of AB. 6. PO is the perpendicular bisector of AB. 6. [ Select ]
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
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![Complete the proof.
Given: Congruent circles OP and O0 have a chord AB on both circles.
Prove: Segment PO is a perpendicular bisector of segment AB.
(Select]
Definition of Radius
Converse of Perpendicular Bisector Theorem
Given
Definition of equidistant
Definition of Perpendicular Bisector
Perpendicular Bisector Theorem
Statements
All radii of the same circle are congruent.
1. Congruent circles OP and C0; chord
AB is on both circles
1.
[ Select]
2. PA, PB, OA, and OB are radii of the
circles.
2. By the construction of the radius /
definition of radius
3. PA PB
3.
[ Select]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F949bd561-9a88-43af-bc19-f4dd0fa13c60%2F9508b046-4792-4ad9-b337-4538f1c8cb78%2Fubw1zau_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Complete the proof.
Given: Congruent circles OP and O0 have a chord AB on both circles.
Prove: Segment PO is a perpendicular bisector of segment AB.
(Select]
Definition of Radius
Converse of Perpendicular Bisector Theorem
Given
Definition of equidistant
Definition of Perpendicular Bisector
Perpendicular Bisector Theorem
Statements
All radii of the same circle are congruent.
1. Congruent circles OP and C0; chord
AB is on both circles
1.
[ Select]
2. PA, PB, OA, and OB are radii of the
circles.
2. By the construction of the radius /
definition of radius
3. PA PB
3.
[ Select]
![Reasons
Statements
1. Congruent circles OP and 00; chord
AB is on both circles
1.
[ Select ]
2. By the construction of the radius /
definition of radius
2. PA, PB, OA, and OB are radii of the
circles.
3. PA PB
3.
[ Select ]
OAN OB
4. Point P is equidistant from points A
and B.
Point O is equidistant from points A
4.
[ Select ]
and B.
5. Point P and Point O lie on the
5.
[ Select ]
perpendicular bisector of AB.
6. PO is the perpendicular bisector of AB. 6. Select]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F949bd561-9a88-43af-bc19-f4dd0fa13c60%2F9508b046-4792-4ad9-b337-4538f1c8cb78%2Fhtyw0bu_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Reasons
Statements
1. Congruent circles OP and 00; chord
AB is on both circles
1.
[ Select ]
2. By the construction of the radius /
definition of radius
2. PA, PB, OA, and OB are radii of the
circles.
3. PA PB
3.
[ Select ]
OAN OB
4. Point P is equidistant from points A
and B.
Point O is equidistant from points A
4.
[ Select ]
and B.
5. Point P and Point O lie on the
5.
[ Select ]
perpendicular bisector of AB.
6. PO is the perpendicular bisector of AB. 6. Select]
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