Rearranged strings Here's a fun little puzzle for you: Given two strings, namely, strings and string t, we'd like to know if it's possible to rearrange the characters within one string to match the character composition of the other string. In other words, can you check if they are anagrams of each other? If it's feasible to rearrange the characters so that both strings contain the same set of characters, return true; otherwise, return false. Remember, an anagram is a word or phrase created by reshuffling the letters from another word or phrase, using all the original letters exactly once. Example 1: Input s: "listen" • Input t: "silent" • Expected Output: True • Explanation: Both "listen" and "silent" are anagrams of each other, as they can be rearranged to have the same set of characters. Example 2: • Input s: "hello" • Input t: "world" • Expected Output: False • Explanation: "hello" and "world" are not anagrams of each other as they have diffe
Rearranged strings Here's a fun little puzzle for you: Given two strings, namely, strings and string t, we'd like to know if it's possible to rearrange the characters within one string to match the character composition of the other string. In other words, can you check if they are anagrams of each other? If it's feasible to rearrange the characters so that both strings contain the same set of characters, return true; otherwise, return false. Remember, an anagram is a word or phrase created by reshuffling the letters from another word or phrase, using all the original letters exactly once. Example 1: Input s: "listen" • Input t: "silent" • Expected Output: True • Explanation: Both "listen" and "silent" are anagrams of each other, as they can be rearranged to have the same set of characters. Example 2: • Input s: "hello" • Input t: "world" • Expected Output: False • Explanation: "hello" and "world" are not anagrams of each other as they have diffe
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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So I got this code from an expert on bartleby but it’s not working and this instructor is saying the indentation is wrong on SEVERAL lines. Someone pls help. Will upvote if it works
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ter's
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Rearranged strings
Here's a fun little puzzle for you: Given two strings, namely,
strings and string t, we'd like to know if it's possible to
rearrange the characters within one string to match the
character composition of the other string. In other words,
can you check if they are anagrams of each other?
Example 2:
If it's feasible to rearrange the characters so that both
strings contain the same set of characters, return true;
otherwise, return false. Remember, an anagram is a word
or phrase created by reshuffling the letters from another
word or phrase, using all the original letters exactly once.
Example 1:
●
Input s: "listen"
Input t: "silent"
• Expected Output: True
Explanation: Both "listen" and "silent" are anagrams of
each other, as they can be rearranged to have the
same set of characters.
• Inputs: "hello"
Input t: "world"
• Expected Output: False
Explanation: "hello" and "world" are not anagrams of
each other as they have different sets of characters
Topic:...
Your ...
Rearranged strings
+
scaffold.py
1. # DO NOT MODIFY THE FUNCTION HEADER
2 # This is autograded. If the autograder cannot run your code,
3 # Your final submission should contain no print statements as
4 def solution (s, t):
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# your code goes here.
s
s.replace(" ", " ").lower ()
t= t.replace(" ", "").lower ()
if len(s) != len(t):
return False
(59) 1...
char_count_s = ()
char_count_t = ()
for char in s:
if char in char_count_s:
char_count_s [char] += 1
char_count_s [char] = 1
else:
for char in t:
if char in char_count_t:
char_count_t[char] += 1
char_count_t[char] = 1
return char_count_s == char_count_t I
else:
/home/scaffold.py Spaces: 4 (Auto)
Terminal
>_
A
★ Challenge
Subm
All changes s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fce303429-f349-4313-b1b6-39c40e965b05%2F6f020e27-1cc5-4bce-88fc-d19d0b3f43d8%2Fw3zwjdc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:ed Discu...
d Lessons
Prev Next
ter's
Grestau...
Description
Look-...
My Cl...
Rearranged strings
Here's a fun little puzzle for you: Given two strings, namely,
strings and string t, we'd like to know if it's possible to
rearrange the characters within one string to match the
character composition of the other string. In other words,
can you check if they are anagrams of each other?
Example 2:
If it's feasible to rearrange the characters so that both
strings contain the same set of characters, return true;
otherwise, return false. Remember, an anagram is a word
or phrase created by reshuffling the letters from another
word or phrase, using all the original letters exactly once.
Example 1:
●
Input s: "listen"
Input t: "silent"
• Expected Output: True
Explanation: Both "listen" and "silent" are anagrams of
each other, as they can be rearranged to have the
same set of characters.
• Inputs: "hello"
Input t: "world"
• Expected Output: False
Explanation: "hello" and "world" are not anagrams of
each other as they have different sets of characters
Topic:...
Your ...
Rearranged strings
+
scaffold.py
1. # DO NOT MODIFY THE FUNCTION HEADER
2 # This is autograded. If the autograder cannot run your code,
3 # Your final submission should contain no print statements as
4 def solution (s, t):
5
6
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10
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# your code goes here.
s
s.replace(" ", " ").lower ()
t= t.replace(" ", "").lower ()
if len(s) != len(t):
return False
(59) 1...
char_count_s = ()
char_count_t = ()
for char in s:
if char in char_count_s:
char_count_s [char] += 1
char_count_s [char] = 1
else:
for char in t:
if char in char_count_t:
char_count_t[char] += 1
char_count_t[char] = 1
return char_count_s == char_count_t I
else:
/home/scaffold.py Spaces: 4 (Auto)
Terminal
>_
A
★ Challenge
Subm
All changes s
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