real numbers that are uniformly distributed between 0 and 100. Find the probability that a random number (X) generated is between 10 and 90. Calculate the mean and variance of X.
real numbers that are uniformly distributed between 0 and 100. Find the probability that a random number (X) generated is between 10 and 90. Calculate the mean and variance of X.
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 11ECP: A manufacturer has determined that a machine averages one faulty unit for every 500 it produces....
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![5. Suppose that a random number generator produces real numbers that are uniformly
distributed between 0 and 100. Suppose that a random number generator produces
real numbers that are uniformly distributed between 0 and 100. Find the probability
that a random number (X) generated is between 10 and 90. Calculate the mean and
variance of X.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3df4203b-6d3e-4d3d-b2db-c99c20c87d89%2Ff5b5b1b8-0ea8-43b7-9461-80474dd55728%2F3xxb21_processed.png&w=3840&q=75)
Transcribed Image Text:5. Suppose that a random number generator produces real numbers that are uniformly
distributed between 0 and 100. Suppose that a random number generator produces
real numbers that are uniformly distributed between 0 and 100. Find the probability
that a random number (X) generated is between 10 and 90. Calculate the mean and
variance of X.
![•Types of functions to express
probability distribution
(a) Probability Mass Function (PMF)
f(x) = P(x = x)
(b) Cumulative Distribution Functions (CDF)
f(x) = P(X ≤ x)
Mean
M = { xf(x)
Variance
0² = [x²f (x) - μ²
Standard Deviation.
0x Tot
Discrete Uniform Distribution
f(x) = //12
M =
0² =
b+ a
2
(b-a+1)²
12
•Binomial Distribution
(f(x) = (~) p² (1-P)^-x
с пр
np(1-P)
1• Hypergeometric Distribution
(*) (*)
(~)
f(x) =
и = пр
8² = np(1-P/(N=1)
where
K/N
P=
·Poisson Distribution
-^+ (^T)*
X!
f(x) = e
M = AT
0² = NT
Where
N = population size
sample size /no. of trials
P
probability
-
p = probability of success on a
single trial
K = no. of successes in the population
in the sample
of
X - no.
successes](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3df4203b-6d3e-4d3d-b2db-c99c20c87d89%2Ff5b5b1b8-0ea8-43b7-9461-80474dd55728%2Fm7nf4p9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:•Types of functions to express
probability distribution
(a) Probability Mass Function (PMF)
f(x) = P(x = x)
(b) Cumulative Distribution Functions (CDF)
f(x) = P(X ≤ x)
Mean
M = { xf(x)
Variance
0² = [x²f (x) - μ²
Standard Deviation.
0x Tot
Discrete Uniform Distribution
f(x) = //12
M =
0² =
b+ a
2
(b-a+1)²
12
•Binomial Distribution
(f(x) = (~) p² (1-P)^-x
с пр
np(1-P)
1• Hypergeometric Distribution
(*) (*)
(~)
f(x) =
и = пр
8² = np(1-P/(N=1)
where
K/N
P=
·Poisson Distribution
-^+ (^T)*
X!
f(x) = e
M = AT
0² = NT
Where
N = population size
sample size /no. of trials
P
probability
-
p = probability of success on a
single trial
K = no. of successes in the population
in the sample
of
X - no.
successes
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