Real Limits for Grouped Frequency Distributions Real Limits IQ f 149.5 - 159.5 150-159 139.5 - 149.5 140-149 2 129.5 - 139.5 130-139 119.5 - 129.5 120-129 6. 109.5 - 119.5 110-119 4 Find the percentile rank of the score "127" 1. Collect all the values required in the formula: Score 127 is in the interval of 120-129 CF below interval: 4 Score: 127 LRL:119.5 Interval size:129.5-119.5=10 (120, 121.122,123, 124,125,126,127,128.129, a total of 10 scores) N = the sum of ALL frequencies =2+2+3+6+4=17 2. Plug into the formula: [( P.R(“127")= (100) 2. II

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Author:Amos Gilat
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Find the percentile rank of "5".
Real Limits for Grouped Frequency Distributions
Real Limits
IQ
f
149.5 - 159.5
150-159
2
139.5 ~ 149.5
140-149
2
129.5 - 139.5
130-139
119.5 - 129.5
120-129
109.5 - 119.5
110-119
4
Find the percentile rank of the score "127"
1. Collect all the values required in the formula:
Score 127 is in the interval of 120-129
CF below interval: 4
Score: 127 LRL:119.5
Interval size:129.5-119.5=10 (120, 121.122,123, 124,125,126,127,128.129, a total of
10 scores)
N = the sum of ALL frequencies =2+2+3+6+4=17
2. Plug into the formula:
)+
P.R(“127")=
(100)
38
Transcribed Image Text:Lets' Try! Find the percentile rank of "5". Real Limits for Grouped Frequency Distributions Real Limits IQ f 149.5 - 159.5 150-159 2 139.5 ~ 149.5 140-149 2 129.5 - 139.5 130-139 119.5 - 129.5 120-129 109.5 - 119.5 110-119 4 Find the percentile rank of the score "127" 1. Collect all the values required in the formula: Score 127 is in the interval of 120-129 CF below interval: 4 Score: 127 LRL:119.5 Interval size:129.5-119.5=10 (120, 121.122,123, 124,125,126,127,128.129, a total of 10 scores) N = the sum of ALL frequencies =2+2+3+6+4=17 2. Plug into the formula: )+ P.R(“127")= (100) 38
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