Real-life heat Capacity is temperature dependent. Consider the formation of water vapor H2(g)+( 02(g) → H20(g) The heat capacities Cp(T) for each of the reactants and the product is given by 2 where the constants a, b and c depend on the substance. The above equation is alid from 298 K to 2,000 K. The units of a, band c are .? Calculate AH given (298 K)=-60kCal. Express your answers in terms of a, b, c for the reactants and roducts (aH2, bH2 --) Answers choices for part b) - AH (T) = -60kCal AH (T) = -60kCal + (aH,0 – aH, - ao.) (T – 298K) + 4 (b#,0 – bí, - bo.) (Tª – 298 K²) – (CH,0 – CH, - co.) ( - ) AH (T) = (a1,0 - a, - j40,) (T – 298K) +(b,0 – bn, – bo,) (7ª – 298* K²) – (cH,0 - CH, - co.) (+ - AK) 208K AH (T) = -60kCal – (aH,0 – aH, - tao.) (T – 298K) – (bH,0 – ba, - bo.) (Tª – 298° K²) + (CH,0 – CH, - co.) ( - )

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Chapter1: Chemical Foundations
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1. Real-life heat Capacity is temperature dependent. Consider the formation of water vapor H2(g)+(
2)O2(g) → H20(g) The heat capacities Cp(T) for each of the reactants and the product is given by
Cp=a+bT+CT 2,
valid from 298 K to 2,000 K.
2 where the constants a, b and c depend on the substance. The above equation is
a. The units of a, b and c are.?
b. Calculate AH given (298 K)=-60kCal. Express your answers in terms of a, b, c for the reactants and
products (aH2, bH2 --)
(Answers choices for part b)
AH (T) = -60kCal
O AH (T) = -60kCal + (an,0 – aH, – tao,) (T – 298K) + + (bH,0 – bH, – bo.) (T² – 298 K²) – (cH,0 – CH, - co.) (÷ - )
AH (T) = (a1,0 – a, – ž40,) (T – 298K) + (b#,0 – bn, – bo,) (Tª – 298* K²) – (cH,0 – CH, – co,) (+ - K)
Ο ΔΗ (T)
= -60kCal – (an,0 – an, - ļa0.) (T – 298K) – |(bH,0 – bH, – įbo.) (T² – 298 K²) + (cH,0 – CH, - co.) ( - )
Transcribed Image Text:1. Real-life heat Capacity is temperature dependent. Consider the formation of water vapor H2(g)+( 2)O2(g) → H20(g) The heat capacities Cp(T) for each of the reactants and the product is given by Cp=a+bT+CT 2, valid from 298 K to 2,000 K. 2 where the constants a, b and c depend on the substance. The above equation is a. The units of a, b and c are.? b. Calculate AH given (298 K)=-60kCal. Express your answers in terms of a, b, c for the reactants and products (aH2, bH2 --) (Answers choices for part b) AH (T) = -60kCal O AH (T) = -60kCal + (an,0 – aH, – tao,) (T – 298K) + + (bH,0 – bH, – bo.) (T² – 298 K²) – (cH,0 – CH, - co.) (÷ - ) AH (T) = (a1,0 – a, – ž40,) (T – 298K) + (b#,0 – bn, – bo,) (Tª – 298* K²) – (cH,0 – CH, – co,) (+ - K) Ο ΔΗ (T) = -60kCal – (an,0 – an, - ļa0.) (T – 298K) – |(bH,0 – bH, – įbo.) (T² – 298 K²) + (cH,0 – CH, - co.) ( - )
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