Reading proficiency: An educator wants to construct a 99.8% confidence interval for the proportion of elementary school children inColorado who are proficient in reading.Part: 0 / 3Part 1 of 3(a) The results of a recent statewide test suggested that the proportion is 0.64. Using this estimate, what sample size is needed sothat the confidence interval will have a margin of error of 0.05?A sample ofelementary school children is needed to obtain a 99.8% confidence interval with amargin of error of 0.05. How's the economy? A pollster wants to construct a 90% confidence interval for the proportion of adults who believe that economicconditions are getting better.Part: 0 / 2Part 1 of 2(a) A poll taken in July 2010 estimates this proportion to be 0.24. Using this estimate, what sample size is needed so that theconfidence interval will have a margin of error of 0.05?A sample ofadults is needed to obtain a 90% confidence interval with a margin of error of 0.05.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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An educator wants to construct a 99% confidence interval for the proportion of elementary school children in Michigan who are proficient in reading. Estimate the sample size needed to conduct this survey and assume that there there is no information available to be used from a previous study. Use a margin of error of 3%. What is the sample size: _________
Use R Studio to answer the following question:
CEO compensation A sample of 20 CEOs from theForbes 500 shows total annual compensations rangingfrom a minimum of $0.1 to $62.24 million. The averagefor these 20 CEOs is $7.946 million. Here’s a histogram:Based on these data, a computer program found that a 95%confidence interval for the mean annual compensationof all Forbes 500 CEOs is (1.69, 14.20) $ million. Whyshould you be hesitant to trust this confidence interval?
The accompanying data set gives the additional sleep in hours obtained by a sample of 10 patients using a certain sleep aid. Preliminary data analyses indicate that the t-interval procedure can reasonably be applied. Complete parts (a) and (b) below. Click here to view the additional sleep hours. Click here to view page 1 of the t-table. Click here to view page 2 of the t-table. ..... a. Obtain and interpret a 99% confidence interval for the additional sleep that would be obtained on average for all people using the sleep aid. (Note: x = 2.50 hr and s= 2.017 hr.) The 99% confidence interval is from hour(s) to hour(s). (Round to two decimal places as needed.) Additional sleep hours 2.2 1.4 0.0 5.7 4.7 1.1 0.1 4.5 1.6 3.7 Print Done
Two brands of tires were compared for the proportion of defective tires. Random samples of tires were collected from each brand, and the number of defective tires from each brand was recorded. The data is in the following table. Number of defective tires (x) 41 32 n Continental Michelin 320 180 a.Construct a 97% confidence interval for the difference between the two proportions. b.For part a, find the desired sample sizes if you want the Continental sample to be 1.5 times Michelin sample with a sampling error equal to 0.03. c. Conduct a test of hypothesis to determine if the defective rates are the same. Use the P-value to interpret the results (a is not given).
Early-childhood-development studies indicate that the more often a child is read to from birth, the earlier the child begins to read. A local parents’ group wants to test this theory and samples families with young children. They find the following results. Construct a 99% confidence interval to estimate the true difference between the proportions of children who read at an early age when they are read to frequently compared to those who were read to less often, as described in the table of results. Let Population 1 be the children who were read to frequently and Population 2 be the children who were read to less often. Round the endpoints of the interval to three decimal places, if necessary. Ages when Children Begin to Read Read to at Least Three Times per Week Read to Fewer than Three Times per Week Started Reading by age 4 60 35 Started Reading after age 4 36 51 Lower end point: Upper end point:
Verizon Wireless would like to estimate the proportion of households that use cell phones for their phone service without a land line. A random sample of 150 households was selected and 48 relied strictly on cell phones for their service. The 95% confidence interval for the proportion based on this sample is ________. A) (0.257, 0.383) B) (0.223, 0.417) C) (0.185, 0.456) D) (0.165, 0.475)
In a study of speed dating, male subjects were asked to rate the attractiveness of their female dates, and a sample of the results is listed below (1=not attractive; 10=extremely attractive). Construct a confidence interval using a 90% confidence level. What do the results tell about the mean attractiveness ratings of the population of all adult females? 5,7,2,9,4,4,6,9,7,8,6,8
in a poll, 73% of California adults (367 out of 506 surveyed) believe that education is one of the main issues facing California. We want to construct a 90% confidence interval for the true proportion of California adults who believe that education is one of the main issues facing California.- I need help with finding a 90% confidence interval for the population proportion (I also have to round the answer to three decimal places)

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