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Level of significance a=0.0802
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- Cell Phone Lifetimes A recent study of the lifetimes of cell phones found the average is 23.2 months. The standard deviation is 3.1 months. If a company provides its 33 employees with a cell phone, find the probability that the mean lifetime of these phones will be less than 23.8 months. Assume cell phone life is a normally distributed variable, the sample is taken from a large population, and the correction factor can be ignored. Use a TI-83 Plus/TI-84 Plus calculator. Round your answer to at least four decimal places. P(X<23.8)=Let's assume that the distribution of gas on a given day in a town is normally distributed with mean of $4.3371 with a standard deviation of $0.4192. What proportion of gas stations are charging less than $3.4387? 98.3949% 0.8026% 1.6051% 3.2103% O 0%Suppose that you expect college freshmen who live on campus will do better academically than those who do not. You select a random sample of 75 freshmen, group them according to where they live, and calculate the following summary statistics. Do these results support your expectations? Assume that the true population standard deviations are equal. Use α = 0.10. Use α = 0.05. What is the p-value of this test?
- The test statistic of z=0.91 is obtained when testing the claim that p>0.29. This is a right-tailed test. Using a 0.10 significance level, complete parts (a) and (b). Click here to view the standard normal distribution table for negative z scores. Click here to view the standard normal distribution table for positive z scores. a. Find the critical value(s). Select the correct choice below and fill in the answer box(es) within your choice. (Round to two decimal places as needed.) OA. There are two critical values; the lower critical value is B. There is one critical value; the critical value is and the upper critical value isThe weight gains of animals during a period of confinement follow a normal distribution of mean 39.0 and standard deviation 1.0 kg. Answer the following questions.a. Above what weight gain are 99% of the animals?The working life of a certain electrical equipment is normally distributed with a mean of 180 days and a standard deviation of 4 days. For each of the following questions, construct a normal distribution curve and provide the answer. About what percent of the products last between 176 and 184 days? About what percent of the products last between 180 and 184 days? For each of the following questions, use the standard normal table and provide the answer. About what percent of the products last 172 or less days? About what percent of the products last 184 or more days?
- This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.Locate the following percentile under the normal curve and find its corresponding t-value. Sketch and label its curve. 1. P95 degree of freedom 6 2. P99 degree of freedom 13 3. P89 degree of freedom 10If P(Z>z1)=0.10 in the standard normal distribution, which of the following is the nearest value for z1? Please select one: a. 2.29 b. 1.96 c. 1.10 d. 1.28 e. 1.64
- Find the sample standard deviation, coefficient of variation, and range. (Round your standard deviation to four decimal places and your coefficient of variation to two decimal places.) Given the following: 1.9, 2.4, 5.7, 4.5, 1.9, 8.5, 3.9, s CV % rangeCell Phone Lifetimes A recent study of the lifetimes of cell phones found the average is 23.8 months. The standard deviation is 5.8 months. If a company provides its 33 employees with a cell phone, find the probability that the mean lifetime of these phones will be less than 23.8 months. Assume cell phone life is a normally distributed variable, the sample is taken from a large population, and the correction factor can be ignored. Use a TI-83 Plus/TI-84 Plus calculator. Round your answer to at least four decimal places. <PX23.8)=In a certain population, let us assume that high school scores are normally distributed with mean of 74 and standard deviation of 15. What is the 75th percentile? Select one: O a. 84.05 O b. 68.15 O c. 79.85 O d. 63.95
