Read eq.(7) to (11) on page 173, 174 and Theorem 4.8.1 on page 175. Then use Green's function, i.e. eq.(10) to solve IVP Sy" – 5y + 6y = 2e' ly(0) = 0, y'(0) = 0

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Chapter2: Second-order Linear Odes
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(c)
Green's function by yourself.
Read eq. (7) to (11) on page 173, 174 and Theorem 4.8.1 on page 175. Then use
Green's function, i.e. eq.(10) to solve IVP
You are now in front of the door and one step close to derive the famous
Jy" – 5y' + 6y = 2e
ly(0) = 0, y'(0) = 0
Yp(x) = u1 (x)y1 (æ) + u2 (x)y2 (x).
(7)
Y2 (æ) f(x)
Y1 (x) f(x)
u (x) =
u (x) =
(8)
W
W
p(x) = y1 (2x) /
pe
-Y2 (t) f(t)
y1 (t) f(t) dt
(2) :
dt + y2 (x)
W(t)
W (t)
(9)
-Y1 (x)y2 (t)
W(t)
Y1 (t)y2 (x)
- f(t) dt,
W (t)
- f(t) dt +
»(#) = / G(x,t)f(t) dt.
(10)
Y1 (t)y2 (x) – y1 (x)y2 (t)
W (t)
-
G(x, t)
(11)
Transcribed Image Text:(c) Green's function by yourself. Read eq. (7) to (11) on page 173, 174 and Theorem 4.8.1 on page 175. Then use Green's function, i.e. eq.(10) to solve IVP You are now in front of the door and one step close to derive the famous Jy" – 5y' + 6y = 2e ly(0) = 0, y'(0) = 0 Yp(x) = u1 (x)y1 (æ) + u2 (x)y2 (x). (7) Y2 (æ) f(x) Y1 (x) f(x) u (x) = u (x) = (8) W W p(x) = y1 (2x) / pe -Y2 (t) f(t) y1 (t) f(t) dt (2) : dt + y2 (x) W(t) W (t) (9) -Y1 (x)y2 (t) W(t) Y1 (t)y2 (x) - f(t) dt, W (t) - f(t) dt + »(#) = / G(x,t)f(t) dt. (10) Y1 (t)y2 (x) – y1 (x)y2 (t) W (t) - G(x, t) (11)
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