Read, analyze and answer the following problems. 1. In a well shuffled standard deck of 52 cards, find the probability of a. king of diamond c. a non-spade cards d. a "2" in black cards b. a red card
Read, analyze and answer the following problems. 1. In a well shuffled standard deck of 52 cards, find the probability of a. king of diamond c. a non-spade cards d. a "2" in black cards b. a red card
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![**Probability Practice Problems**
**Instructions:**
Read, analyze, and answer the following problems.
1. **In a well-shuffled standard deck of 52 cards, find the probability of:**
- a. a king of diamond
- b. a red card
- c. a non-spade card
- d. a “2” in black cards
2. **A coin is tossed 7 times**
- a. What is the probability that the coin will land tails all 7 times?
- b. What is the probability that the coin will land heads on the first and the last toss?
3. **A pair of dice is tossed, what is the probability of obtaining a sum of 4?**
4. **If a card is drawn from a shuffled deck of 52 cards, find the probability of drawing a black jack card**
5. **A box contains 6 blue chips and 3 green chips. If 2 chips are drawn at random:**
- a. What is the probability that they are of different colors?
- b. What is the probability that the chips are both blue?
**Note:**
Please ensure you understand the basic probability concepts before attempting to solve these problems. Probability can be calculated as the number of favorable outcomes divided by the total number of possible outcomes.
**Example Problem Explanation:**
_For problem 1a:_
- There are 52 cards in a deck and only 1 king of diamonds. The probability P is, therefore, 1 out of 52, which is calculated as:
\[
P(\text{king of diamond}) = \frac{1}{52}
\]
_For problem 3:_
- To find the probability of obtaining a sum of 4 when two dice are tossed, list all possible outcomes:
- (1, 3), (2, 2), and (3, 1)
- There are 3 favorable outcomes.
- The total number of possible outcomes when two dice are thrown is 6 × 6 = 36.
- Thus, the probability P is:
\[
P(\text{sum of 4}) = \frac{3}{36} = \frac{1}{12}
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Transcribed Image Text:**Probability Practice Problems**
**Instructions:**
Read, analyze, and answer the following problems.
1. **In a well-shuffled standard deck of 52 cards, find the probability of:**
- a. a king of diamond
- b. a red card
- c. a non-spade card
- d. a “2” in black cards
2. **A coin is tossed 7 times**
- a. What is the probability that the coin will land tails all 7 times?
- b. What is the probability that the coin will land heads on the first and the last toss?
3. **A pair of dice is tossed, what is the probability of obtaining a sum of 4?**
4. **If a card is drawn from a shuffled deck of 52 cards, find the probability of drawing a black jack card**
5. **A box contains 6 blue chips and 3 green chips. If 2 chips are drawn at random:**
- a. What is the probability that they are of different colors?
- b. What is the probability that the chips are both blue?
**Note:**
Please ensure you understand the basic probability concepts before attempting to solve these problems. Probability can be calculated as the number of favorable outcomes divided by the total number of possible outcomes.
**Example Problem Explanation:**
_For problem 1a:_
- There are 52 cards in a deck and only 1 king of diamonds. The probability P is, therefore, 1 out of 52, which is calculated as:
\[
P(\text{king of diamond}) = \frac{1}{52}
\]
_For problem 3:_
- To find the probability of obtaining a sum of 4 when two dice are tossed, list all possible outcomes:
- (1, 3), (2, 2), and (3, 1)
- There are 3 favorable outcomes.
- The total number of possible outcomes when two dice are thrown is 6 × 6 = 36.
- Thus, the probability P is:
\[
P(\text{sum of 4}) = \frac{3}{36} = \frac{1}{12}
\]
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