reacts with gaseous oxygen gas (0₂) to produce gaseous carbon dioxide (CO₂) and gaseous water (H₂O). If 89.6 g of Liquid octane carbon dioxide is produced from the reaction of 85.66 g of octane and 117.0 g of oxygen gas, calculate the percent yield of carbon dioxide. Round your answer to 3 significant figures. X 3 of
reacts with gaseous oxygen gas (0₂) to produce gaseous carbon dioxide (CO₂) and gaseous water (H₂O). If 89.6 g of Liquid octane carbon dioxide is produced from the reaction of 85.66 g of octane and 117.0 g of oxygen gas, calculate the percent yield of carbon dioxide. Round your answer to 3 significant figures. X 3 of
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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---
### Chemical Reactions: Percent Yield of Chemical Reactions
The problem involves the combustion reaction of octane with oxygen to produce carbon dioxide and water. The goal is to calculate the percent yield of carbon dioxide based on the given masses.
#### The Reaction:
\[
\text{Liquid octane} \, (\text{CH}_3(\text{CH}_2)_6\text{CH}_3) \, \text{reacts with gaseous oxygen gas} \, (\text{O}_2) \, \text{to produce gaseous carbon dioxide} \, (\text{CO}_2) \, \text{and gaseous water} \, (\text{H}_2\text{O}).
\]
#### Data Given:
- **Mass of octane used** = 85.66 g
- **Mass of oxygen gas used** = 117.0 g
- **Mass of carbon dioxide produced** = 89.6 g
#### Task:
Calculate the percent yield of carbon dioxide and round the answer to 3 significant figures.
### Explanation:
1. **Balanced Equation**: Write the balanced chemical equation for the combustion of octane.
2. **Theoretical Yield**: Use stoichiometry to calculate the theoretical yield of carbon dioxide from the given masses of octane and oxygen.
3. **Percent Yield Calculation**:
\[
\text{Percent Yield} = \left(\frac{\text{Actual Yield}}{\text{Theoretical Yield}}\right) \times 100
\]
Plug in the values to find the percent yield.
#### Instructions:
Input your solution in the space provided and click "Check" to verify your answer.
---
This explanation covers how to approach solving the problem regarding percent yield in a combustion reaction.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffc5d9ab7-5262-4222-989c-d8b3bd159f6f%2F4119377d-2275-4ece-bb96-06fd9f6b538b%2Fjcox4up_processed.jpeg&w=3840&q=75)
Transcribed Image Text:I'm unable to transcribe the text from the image directly, but I can help explain it.
---
### Chemical Reactions: Percent Yield of Chemical Reactions
The problem involves the combustion reaction of octane with oxygen to produce carbon dioxide and water. The goal is to calculate the percent yield of carbon dioxide based on the given masses.
#### The Reaction:
\[
\text{Liquid octane} \, (\text{CH}_3(\text{CH}_2)_6\text{CH}_3) \, \text{reacts with gaseous oxygen gas} \, (\text{O}_2) \, \text{to produce gaseous carbon dioxide} \, (\text{CO}_2) \, \text{and gaseous water} \, (\text{H}_2\text{O}).
\]
#### Data Given:
- **Mass of octane used** = 85.66 g
- **Mass of oxygen gas used** = 117.0 g
- **Mass of carbon dioxide produced** = 89.6 g
#### Task:
Calculate the percent yield of carbon dioxide and round the answer to 3 significant figures.
### Explanation:
1. **Balanced Equation**: Write the balanced chemical equation for the combustion of octane.
2. **Theoretical Yield**: Use stoichiometry to calculate the theoretical yield of carbon dioxide from the given masses of octane and oxygen.
3. **Percent Yield Calculation**:
\[
\text{Percent Yield} = \left(\frac{\text{Actual Yield}}{\text{Theoretical Yield}}\right) \times 100
\]
Plug in the values to find the percent yield.
#### Instructions:
Input your solution in the space provided and click "Check" to verify your answer.
---
This explanation covers how to approach solving the problem regarding percent yield in a combustion reaction.
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