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Reaction Type:_ At completion of reactions: Grams of methane Grams of oxygen Grams of carbon dioxide Grams of water vapor

Reaction Type:_ At completion of reactions: Grams of methane Grams of oxygen Grams of carbon dioxide Grams of water vapor

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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7. CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H₂O (g) (This is just stoichiometry.) Reaction Type: Combustion Grams of Product (List the Product and the Amount): 1.18 x 10g CH4 and 9.70 x 10 g H₂0 ? g CO₂ 4.32 ng CH4 x 1g CH4 X 1x 10° ng CH4 1 mol CH4 x 1 mol CO₂ x 44.01 g CO₂ 16.05 g CH 1 mol CH4 1 mol CO₂ ? g H₂O= 4.32 ng CH4 x X 1g CH4 1 x 10" ng CH4 g 2₂ used = 1 mol CH4 x 16.05 g CH₂ 2 mol O₂ 1 mol CH4 4.32 пусна х 12 сна (LR) Amount of O₂ Remaining in = the container = 2 mol H₂O x 18.02 g H₂0 1 mol CH4 1 mol H₂O O₂ amount given x 15.999 0₂ amount of O₂ remaining - 1mol CH₂ X 1X10³ ng CH₂ 16.05 g CH₂ Imel 0₂ =1.18 x 108 = = 70.429 X10-8g Yemaining Q amount used g CH₂ 9.70 x 10 ºg H₂0 = 0.429x10-8g = 0.861 x 10 g ₂ 0₂ used 4.32 X10 g ₂ given -0.861×108/0₂ 10³ = 0.432 X10-8 -0.861 × 10-8g 0₂ led g used X Answer
Transcribed Image Text:7. CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H₂O (g) (This is just stoichiometry.) Reaction Type: Combustion Grams of Product (List the Product and the Amount): 1.18 x 10g CH4 and 9.70 x 10 g H₂0 ? g CO₂ 4.32 ng CH4 x 1g CH4 X 1x 10° ng CH4 1 mol CH4 x 1 mol CO₂ x 44.01 g CO₂ 16.05 g CH 1 mol CH4 1 mol CO₂ ? g H₂O= 4.32 ng CH4 x X 1g CH4 1 x 10" ng CH4 g 2₂ used = 1 mol CH4 x 16.05 g CH₂ 2 mol O₂ 1 mol CH4 4.32 пусна х 12 сна (LR) Amount of O₂ Remaining in = the container = 2 mol H₂O x 18.02 g H₂0 1 mol CH4 1 mol H₂O O₂ amount given x 15.999 0₂ amount of O₂ remaining - 1mol CH₂ X 1X10³ ng CH₂ 16.05 g CH₂ Imel 0₂ =1.18 x 108 = = 70.429 X10-8g Yemaining Q amount used g CH₂ 9.70 x 10 ºg H₂0 = 0.429x10-8g = 0.861 x 10 g ₂ 0₂ used 4.32 X10 g ₂ given -0.861×108/0₂ 10³ = 0.432 X10-8 -0.861 × 10-8g 0₂ led g used X Answer
7. Balanced Chemical Equation Reaction Type: At completion of reactions: Grams of methane Grams of oxygen Grams of carbon dioxide Grams of water vapor
Transcribed Image Text:7. Balanced Chemical Equation Reaction Type: At completion of reactions: Grams of methane Grams of oxygen Grams of carbon dioxide Grams of water vapor
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