Reach Width(m) Discharge(m3/s) Slope Normal depth (m) A 3.5 10.0 0.0004 2.736 B 3.0 10.0 0.0160 0.663 Critical depth = B8/3 = 2.736m CDL 1 Yca Yob = NDL 1 Normal depth From table 3A-1, You/B₁ = 0.7816 nQ 0.015×10.0 √S 3.0%/3x0.0161/2 (10.0/3.5) ₁1/3=0.941m 9.81 0.941m (10.0/3.0)/³ = 1.042m 9.81 Channel A nQ B8/3 So 0.020x10.0 3.58/3 ×0.0004¹/2 = 0.063344 From table 3A-1, Yob/B₁ = 0.221 Sketch the resulting GVF profiles in figure 1 due to change in the channel characteristics as above. ==> = 0.35412 ==> You = 2.736 Yob = 0.663m Channel B 1.042m CDL 2 NDL 2 0.663m Figure 1
Reach Width(m) Discharge(m3/s) Slope Normal depth (m) A 3.5 10.0 0.0004 2.736 B 3.0 10.0 0.0160 0.663 Critical depth = B8/3 = 2.736m CDL 1 Yca Yob = NDL 1 Normal depth From table 3A-1, You/B₁ = 0.7816 nQ 0.015×10.0 √S 3.0%/3x0.0161/2 (10.0/3.5) ₁1/3=0.941m 9.81 0.941m (10.0/3.0)/³ = 1.042m 9.81 Channel A nQ B8/3 So 0.020x10.0 3.58/3 ×0.0004¹/2 = 0.063344 From table 3A-1, Yob/B₁ = 0.221 Sketch the resulting GVF profiles in figure 1 due to change in the channel characteristics as above. ==> = 0.35412 ==> You = 2.736 Yob = 0.663m Channel B 1.042m CDL 2 NDL 2 0.663m Figure 1
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
In a rectangular channel two reaches A and B in series, with reach A being upstream of reach B, have the following characteristics:
![Reach Width(m) Discharge(m3/s) Slope Normal depth (m)
A
3.5
10.0
0.0004
2.736
B
3.0
10.0
0.0160
0.663
Critical depth
=
B8/3
=
Yca
2.736m
CDL 1
=
Y₁ = = [²
=
(10.0/3.5) ₁1/3
9.81
(10.0/3.0)².
9.81
Normal depth
From table 3A-1, You/B₁ = 0.7816
nQ
0.015×10.0
√So 3.08/3×0.0161/2
0.941m
nQ
B8/3
√S
Channel A
= 0.941m
-]¹/³ = 1.042m
0.020×10.0
3.58/3x0.00041/2
= 0.063344
From table 3A-1, Yob/B₁ = 0.221
Yob = 0.663m
Sketch the resulting GVF profiles in figure 1 due to change in the
channel characteristics as above.
NDL 1
==>
= 0.35412
==>
You = 2.736
Channel B
1.042m
CDL 2
NDL 2
0.663m
Figure 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F03459b59-f1b3-470d-8d98-5fb5b01f9b6f%2Fc4f2c91d-82f4-40c5-b0c0-8eac02d25b2e%2F9w730hj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Reach Width(m) Discharge(m3/s) Slope Normal depth (m)
A
3.5
10.0
0.0004
2.736
B
3.0
10.0
0.0160
0.663
Critical depth
=
B8/3
=
Yca
2.736m
CDL 1
=
Y₁ = = [²
=
(10.0/3.5) ₁1/3
9.81
(10.0/3.0)².
9.81
Normal depth
From table 3A-1, You/B₁ = 0.7816
nQ
0.015×10.0
√So 3.08/3×0.0161/2
0.941m
nQ
B8/3
√S
Channel A
= 0.941m
-]¹/³ = 1.042m
0.020×10.0
3.58/3x0.00041/2
= 0.063344
From table 3A-1, Yob/B₁ = 0.221
Yob = 0.663m
Sketch the resulting GVF profiles in figure 1 due to change in the
channel characteristics as above.
NDL 1
==>
= 0.35412
==>
You = 2.736
Channel B
1.042m
CDL 2
NDL 2
0.663m
Figure 1
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