Note: In Problems 7between (a) A = 3î – 2j and B = 4î – 4j, (b) Ã= -2i +4j(b) from x = 5.00 m to x = 10.0 m, and (c) from .as shown in Figure P7.9. Find the work done by the force9. A particle is subject to a force F. that varies with positionthree significant figures as usual.118°32.8 N-132°17.3 cmFigure P7.78. Using the definition of the scalar product, find the anglebetween (a) A = 3i – 2î and B = 4î – 4î, (b) Ã= -21 +4)and B= 31 - 4i + 2k, and (c)Ã=Î - 2j + 2k and3j + 4k.|SECTION 7.4 Work Done by a Varying ForceVon the particle as it moves (a) from x =0 to x = 5.00 m,x = 10.0 mto x = 15.0 m. (d) What in tlover the d'hu the force

“Since you have asked multiple question, we will solve the first question for you. If you want any specific question to be solved then please specify the question number or post only that question.”7. Given f=32.8N and r=17.3cm=0.173m Let's assume angle between f and r is θ. Then from diagram we can see the angle of three quadrant is 118⁰+θ+132⁰=270⁰ Or x=20⁰Therefore the scalar product is S = f.r.cosθ =32.8x0.173 cos(20⁰) Or S=5.33N.m This is the answer.

Answered: re sig Find the scalar product of the…

re sig Find the scalar product of the vectors in Figure P7.7. 118° 32.8 N- 132° 17.3 cm Figure P7.7